通过带有参数的石墨烯查询mongoDB

问题描述 投票:1回答:2

早上好,

我希望能够提出一个GraphQL请求,以“询问” MongoDB以下问题:

query 
{ user(firstname:"Pierre}
    { lastname}
}
  • 为此,我定义了一个model.py:
from mongoengine import Document
from mongoengine.fields import StringField
class User(Document):
    meta = {'collection': 'user'}
    firstname = StringField(required=True)
    lastname = StringField(required=True)
  • 然后我已经在Schema.py中定义了:
from graphene_mongo import MongoengineObjectType
from graphene import connect
from models import User as UserModel

connect(db="graphene-mongo-example",host="127.0.0.1:27017",alias="default")

class User(MongoengineObjectType):
    class Meta:
        model = UserModel

class Query(graphene.ObjectType):

    users = graphene.List(User)

    def resolve_users(self, info,firstname):
        return list(UserModel.objects.all(firstname))

schema = graphene.Schema(query=Query)

我仅拥有具有给定名字的用户,但没有成功。您能帮我吗?

非常感谢

B。

mongodb graphql mongoengine graphene-python
2个回答
0
投票

查询{user(名字:“ Pierre} {lastname}}

如果上面是您的graphql查询,那么应该是

查询

{用户(名字:“ Pierre”){姓氏}}

接下来,请在您的代码中读取此参数的名字,并相应地获取文档


0
投票

models.py不变。这是我为回答我遇到的问题而编写的代码:

import graphene
from graphene.relay import Node
from flask import Flask
from flask_graphql import GraphQLView
from graphene_mongo import MongoengineObjectType
from models import User as UserModel
from mongoengine import connect


connect(db="graphene-mongo-example",host="127.0.0.1:27017",alias="default")


class User(MongoengineObjectType):
    class Meta:
        model = UserModel
        filter_fields = ['fisrt_name']
        interfaces = (Node,)

class Query(graphene.ObjectType):
    user_by_name = graphene.Field(User,gName=graphene.String())

    def resolve_user_by_name(parent,info,gName):
       return UserModel.objects.get(first_name=gName)

schema = graphene.Schema(query=Query)

#==================================================================

app = Flask(__name__)
app.debug = True
app.add_url_rule(
    "/graphql", view_func=GraphQLView.as_view("graphql", schema=schema, graphiql=True)
  )

if __name__ == "__main__":
    app.run()

然后我就可以用GraphQL查询这种请求:

query { 
userByName(gName:"Pierre")
  {lastName 
   firstName
  }
}
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