我尝试阅读但仍然无法弄清楚如何处理此请求:
我有这样一张桌子:
id_news id_category id_opinion
113 5 152
112 5 152
152 8 0
153 8 0
114 5 153
115 5 153
我想把我的帖子称为id_category 5&8和id_news,就像id_opinion一样我正在做这个陈述,但我不认为这是正确的
select * from news where id_category = '5' AND id_category='8' AND id_news = id_opinion
谢谢
你需要使用OR
作为id_category
,例如:
SELECT *
FROM news
WHERE (id_category = '5' OR id_category='8') AND id_news = id_opinion;
另一种选择是使用IN
,例如:
SELECT *
FROM news
WHERE id_category IN ('5', '8') AND id_news = id_opinion;
您可以使用IN运算符来过滤id_category 5和8:
SELECT *
FROM news
WHERE id_category IN ('5', '8') AND id_news = id_opinion;
这可能有效。
SELECT c.`id_news` as `newsId`,c.id_category as `Category`,c.id_opinion as `opinion`,d.`id_news` as `newsId1`,d.id_category as `Category1`,d.id_opinion as `opinion1`
from news as c
JOIN news as d on c.`id_news` = d.`id_opinion`
where c.id_category in(5,8)