借助this answer,我可以计算Python中一个时间增量列表的平均值。
timedeltas = [ ... ]
# giving datetime.timedelta(0) as the start value makes sum work on tds
average_timedelta = sum(timedeltas, datetime.timedelta(0)) / len(timedeltas)
是否存在用于获取列表中时间增量中值的解决方案?
使用statistics.median()
例如:
import statistics
timedeltas = [1,2,3,4,5,6]
print(statistics.median(timedeltas))