SAP HANA - SQL - 在没有递归函数的情况下计算同一个表上的列

问题描述 投票:0回答:1

我有下面的简单表格,大约有。 40k 项目:

|date|consum|

基于这个表,我想计算一些新的列。最后,表格应该是这样的:

|date|consum|row|row_relativ|min|max|upper|lower|

很遗憾,SAP HANA 数据库不支持递归表语句...

计算规则如下:

  1. 行=
    row_number() over(order by dates)
  2. row_relative =
    row*35040/32768
  3. 分钟 =
    floor(row_relative)
  4. 最大 =
    ceil(row_relative)
  5. min = 从具有最小值的行中选择消耗量
  6. max = 从具有最大值的行中选择 consum

目前我有一个包含 5 个变量的存储过程。在每个变量中,我计算 1 个新列。它非常非常脏……我怎样才能让它与众不同?我不能使用递归函数...:/

这是我的 SQL 片段...玩得开心 =)

var1 = select *, row_number() over(order by dates) as row from XYZ order by dates limit 34944;
var2 = select *, (row * 34944/32768) as row_relative from :var1;
var3 = select *, floor(row_relative) as min, ceil(row_relative) as max from :var2;

var4 = select 
    p.*,
    (select consumfrom :var3 where row = p.min) as lower,
    (select consumfrom :var3 where row = p.max) as upper
from :var3 p;

var5 = select 
    p.*,
    (p.lower* (1-p.row_relative+p.min)+p.upper * (p.row_relativ - p.min)) as new_consum
from :var4 p;
hana
1个回答
0
投票

您可以在 SQLScript 中使用以下 CTE 公用表表达式 顺便说一句,非常有趣的是,几乎相同的 SQL Server CTE 语法与 SAP HANA SQLScript 语法匹配:)

with cte as (
select
    date,
    consum,
    row_number() over (order by date) as row
from rawdata
)
select
    date,
    consum,
    row,
    row * 35040 / 32768 as row_relative,
    floor( (row * 35040 / 32768) ) as min,
    ceil( (row * 35040 / 32768) ) as max,
    (select cte2.consum from cte cte2 where row = floor( (cte.row * 35040 / 32768) ) ) as min2,
    (select cte2.consum from cte cte2 where row = ceil( (cte.row * 35040 / 32768) ) ) as max2
from cte
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