SELECT DISTINCT 在匹配任一值的两列之间查询

Question

我有以下表格：

TABLE_A

|      some_id      | entity_id| tableB_id| position |
|-------------------|----------|----------|----------|
|         388       |     8    |    5783  |    0     |
|         389       |     8    |    776   |    1     |
|         390       |     8    |    5765  |    2     |
|         391       |     8    |    5743  |    3     |
|         392       |     8    |    6167  |    4     |
|         393       |     8    |    6168  |    5     |
|         394       |     8    |    6169  |    6     |
|         708       |     11   |    501   |    3     |

TABLE_B

|     some_id       |  key_1  |     key2      | tableC_id |isSomeCheck|isOtherCheck|
|-------------------|---------|-------------- |-----------|-----------|------------|
|     776           | null    |   pqrstuvw1234|    311    |    1      |     0      |
|    5743           | sfrwt0  |   sofdsfsdr456|    1829   |    1      |     0      |
|    5765           | null    |   abcdefgh4567|    321    |    1      |     0      |
|    5783           | null    |   something341|    1841   |    1      |     0      |
|    6167           | somer9  |   null        |    1956   |    0      |     0      |
|    6168           | richt6  |   null        |    1957   |    0      |     0      |
|    6169           | done60  |   null        |    1957   |    0      |     0      |

TABLE_C

|     some_id       |  key_1   | sortName |
|-------------------|----------|----------|
|       311         |  tes456  |    WWW   |
|       321         |  don890  |    UNK   |
|      1829         |  som123  |    ILA   |
|      1841         |  ken980  |    ARI   |
|      1956         |  lam123  |    KOR   |
|      1957         |  kes648  |    ERO   |

isSomeCheck

或

isOtherCheck

必须为 1.

我正在运行的当前查询返回结果，其中只有 TABLE_B 中的 key_1 存在：

SELECT  TABLE_A.some_id FROM TABLE_B
    JOIN TABLE_A
        ON TABLE_A.tableB_id = TABLE_B.some_id
    JOIN     (SELECT tableB.some_id AS tableBID,
            tableC.sortName  AS tableCSortName
     FROM   TABLE_B AS tableB
            INNER JOIN TABLE_C AS tableC
                    ON tableB.tableC_id = tableC.some_id
     GROUP  BY tableB.some_id)
        ON TABLE_A.tableB_id = tableBID WHERE TABLE_B.key_1 in (select distinct(key_1) from TABLE_B where key_1 = TABLE_B.key_1 and TABLE_B.isRequired = 1 or TABLE_B.isChecked = 1) AND entity_id = 8  ORDER BY TABLE_A.position

输出：

|      some_id      |
|-------------------|
|         391       |

一切正常，除了如果 TABLE_B 中缺少 key_1 并且 key_2 像 OR 条件一样存在，我还想从 TABLE_A 中获取

some_id

。基本上，我也想在输出中考虑 key_2。

所以，我的预期输出是这样的：

|      some_id      |
|-------------------|
|         388       |
|         389       |
|         390       |
|         391       |

我试过并返回correct输出：

SELECT  TABLE_A.some_id FROM TABLE_B
    JOIN TABLE_A
        ON TABLE_A.tableB_id = TABLE_B.some_id
    JOIN     (SELECT tableB.some_id AS tableBID,
            tableC.sortName  AS tableCSortName
     FROM   TABLE_B AS tableB
            INNER JOIN TABLE_C AS tableC
                    ON tableB.tableC_id = tableC.some_id
     GROUP  BY tableB.some_id)
        ON TABLE_A.tableB_id = tableBID
        WHERE 
        (TABLE_B.key_2 in (select distinct(key_2) from TABLE_B where key_2 = TABLE_B.key_2 and TABLE_B.isSomeCheck = 1 or TABLE_B.isOtherCheck = 1) or
        TABLE_B.key_1 in (select distinct(key_1) from TABLE_B where key_1 = TABLE_B.key_1 and TABLE_B.isSomeCheck = 1 or TABLE_B.isOtherCheck = 1))
        AND entity_id = 8  ORDER BY TABLE_A.position;

这是实现我需要的输出的正确方法，还是有更好的方法来实现这个，以便我可以在上面的查询中更新

WHERE

子句？

我想删除在两个选择不同的查询中检查 isSomeCheck 和 isOtherCheck 的重复代码。谢谢！