我刚刚在代码中添加了一个函数,该函数应该显示目录中的图像。它需要一个参数来指定将其显示在哪个窗口中。当我尝试传递它时,收到以下错误:
Traceback (most recent call last):
File "Pygame.py", line 122, in <module>
Player.load()
File "Pygame.py", line 74, in load
screen.blit(self.path, (self.x, self.y))
TypeError: argument 1 must be pygame.Surface, not str
我的代码:
import pygame
#init the pygame and create a screen
pygame.init()
screen = pygame.display.set_mode((1080,720))
done = False
#colours
blue = (0,0,255)
red = (255,0,0)
green = (0,255,0)
black = (0,0,0)
white = (255,255,255)
yellow = (255,255,0)
#path to the background
bg_path = "Racing.png"
#path to the car image
car_path = "car.png"
#starts the game clock
clock = pygame.time.Clock()
#opening bg image
background_image = pygame.image.load(bg_path).convert()
#class for all of the objects on the screen
class shape():
def __init__(self, place, x, y):
self.place = place
self.x = x
self.y = y
class rectangle(shape):
def __init__(self, place, colour, x, y, length, width):
super().__init__(place,x, y)
self.colour = colour
self.length = length
self.width = width
def draw(self):
pygame.draw.rect(screen, self.colour, pygame.Rect(self.x, self.y,
self.length, self.width))
def move_up(self):
self.y = self.y - 10
def move_down(self):
self.y = self.y + 10
def move_right(self):
self.x = self.x + 10
def move_left(self):
self.x = self.x - 10
class player(shape):
def __init__(self, place, x, y, length, width, path):
super().__init__(place,x, y)
self.length = length
self.width = width
self.path = path
def load(self):
screen.blit(self.path, (self.x, self.y))
Rectangle = rectangle(screen, yellow, 540, 660, 60, 60)
Player = player(screen, 540, 600, 60, 60, car_path)
Player.load()
这不是全部代码,但其余与问题无关(我认为)。请告诉我是否需要更多代码。
[car_path
在此处设置为string
car_path = "car.png"
但是blit()
要求pygame.Surface
为您提供的第一个参数是pygame.image.load
对象,>
pygame.image.load
代替。