如何使用中值滤波算法消除胡椒噪声

问题描述 投票:1回答:1

我已经编写了一个代码(使用C ++),使用CImg库在图像中添加了噪点。现在我想给图像加载噪声,并使用中值滤波算法消除图像内部的那些噪声。下面是我的代码。

int main()
{
    int x;
    cout<<"Welcome to my app\n";
    cout<<"Choose options below\n";
    cout<<"1. Remove pepper    2. Add pepper\n";
    cin>>x;
    if (x==1)
    {
        cout<<"Needs help";
        /* 
        * i tried to change the noise level to 0 but it did not work like below 
        * image.noise(0,2); 
        * 
        */
    }
    else if(x==2)
    {
        //image file
        CImg<unsigned char> image("new.bmp");
        const unsigned char red[] = { 255,0,0 }, green[] = { 0,255,0 }, blue[] = { 0,0,255 };
        image.noise(100,2);
        image.save("new2.bmp");
        CImgDisplay main_disp(image, "Image with Pepper noise");
        while (!main_disp.is_closed())
            {
                main_disp.wait();               
            }
    }

    getchar();
    return 0;

}

如果有使用CImg库的另一种方式,我将非常感激!!

c++ cimg
1个回答
0
投票

根据this tutorialthe median函数的定义,您将获得类似以下内容:

#include <algorithm>
using namespace std;
// ...
int ksize = 3; // 5, 7, N and so on... for NxN kernel
int ksize2 = ksize/2;
vector<uchar> kernel(ksize*ksize, 0);
for (int i=ksize2;i<image.dimx() - ksize2;i++)
    for (int j=ksize2;j<image.dimy() - ksize2;j++)
        for (int k=0;k<3;k++) {
            // prepare kernel
            int n = 0;
            for(int l = -ksize2; l <= ksize2; l++)
                for(int m = -ksize2; m <= ksize2; m++)
                    kernel[n++] = image(i + l,j + m,0,k); 

            // using std::algorithm to find median
            sort(kernel.begin(), kernel.end());

            // simple assign median value to created empty image
            medianFilteredImage(i, j, 0, k) = kernel[kernel.size()/2]; // median is here now
        }
    }
}
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