Scrapy。通过其内容查找标签

Question

如何通过其内容查找标签？这是我找到必要元素的方式，但是某些页面上的结构不同，因此并不总是有效。

yield {
            ...
            'Education': response.css('.provider-item:nth-child(3) .h2-style+ span::text').get(),
            'Training': response.css('.provider-item:nth-child(4) .h2-style+ span::text').get(),
            ...                
        }

Answer 1

检查代码示例

In [4]: i = response.xpath('.//span[contains(text(),"Education")]')

In [5]: i
Out[5]: [<Selector xpath='.//span[contains(text(),"Education")]' data='<span class="listing-h2 h2-style">Edu...'>]

In [6]: i.xpath('following-sibling::span[1]/text()').extract()
Out[6]:
['A.B. in Economics with a minor in Asian Studies, ',
 'Occidental College',
 'Masters in Chinese Medicine, Tai Hsuan Foundation']

Answer 2

如果您想一次从div.provider-item标签中提取所有数据点，则可以尝试此操作（如果span.h2标签中的“键”和value标签中的具有span属性的itemprop，则>

data = {}
for item in response.css("div.provider-item"):
    key = item.css("span.listing-h2.h2-style::text").extract_first()
    value = item.css("span[itemprop]::text").extract()
    #value = item.css("span::text").extract()[1:]
    data[key] = value
如果每个div.provider-item标签都严格包含2个span标签，则可以尝试以下操作：

data = {}
for item in response.css("div.provider-item"):
    key, value = item.css("span::text").extract()
    data[key] = value