我想提出一个表,如下所示:
CREATE TABLE creator.lists
(
_id bigserial PRIMARY KEY NOT NULL,
account_id bigint NOT NULL,
created timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP,
display_name text DEFAULT '',
name text DEFAULT '',
extra jsonb,
FOREIGN KEY (account_id)
REFERENCES creator.accounts (_id)
ON DELETE CASCADE
);
但我得到这个错误:
ERROR: relation "account_id_index" already exists
当我运行:
CREATE INDEX
account_id_index
ON
creator.lists
(
account_id
);
如何创建外键索引?我正在V11.1
刚一说明,那我也跑前类似的命令另一个表:
CREATE INDEX
account_id_index
ON
creator.contacts
(
account_id
);
我不假设索引名必须是表之间的独特之处?
索引住在同一个命名空间表,视图和序列号,以便在一个模式中,你不能对任何对象使用相同的名称两次。
要么选择一个不同的名称,或有PostgreSQL的选择一个给你:
CREATE INDEX ON creator.lists (account_id);
好吧,好像索引名必须是唯一的去掉了命名固定它:
CREATE INDEX
ON
creator.contacts
(
account_id
);
从docs:
name
The name of the index to be created. No schema name can be included here; the index is always created in the same schema as its parent table. If the name is omitted, PostgreSQL chooses a suitable name based on the parent table's name and the indexed column name(s).