在类中的所有方法中验证相同的内容。避免代码重复

问题描述 投票:1回答:1

Obs:当然我可以创建一个验证方法,并在我所有其他方法中调用此方法。但我想知道做一些我一直想的事情是否可行。

我需要的:

我有一个类,我的所有方法都应验证它接收的参数(一个对象)是否为None,以及它是否具有特定方法。让我们简单一点。

我想知道是否有类似以下代码的简单内容。

这是一个例子:

def validate(obj):
    return not obj or obj.can_validate()

class MyClass:

    def __init__(self):
        pass

    @validate(obj)
    def my_method_1(self, obj):
        print(obj)

    @validate(obj)
    def my_method_2(self, obj):
        print(obj)

    @validate(obj)
    def my_method_3(self, obj):
        print(obj)


class Validator1:

    def __init__(self):
        pass

class Validator2:

    def __init__(self):
        pass

    def can_validate(self):
        pass

my_class = MyClass()

obj_1 = None
obj_2 = Validator1()
obj_3 = Validator2()

print(x.my_method_1(obj_1))
print(x.my_method_2(obj_2))
print(x.my_method_3(obj_3))

# The output would be something like this>>
# output:
# <empty line because obj_1 is None>
# <empty line because obj_2 has no method can_validate()>
# __Class__...something <since it's not none and has can_validate() method>

如果没有类似的东西,最干净和正确的方法应该是什么,避免代码重复和“大量代码”?

python validation properties reusability
1个回答
1
投票

只需对现有代码进行最少的更改:

def validate(func):
    def modified(self, obj):
        if obj and hasattr(obj, 'can_validate'):
            return func(self, obj)
        return None  # None will be printed. Change it to '' to print empty line
    return modified


class MyClass:

    def __init__(self):
        pass

    @validate
    def my_method_1(self, obj):
        print(obj)

    @validate
    def my_method_2(self, obj):
        print(obj)

    @validate
    def my_method_3(self, obj):
        print(obj)


class Validator1:

    def __init__(self):
        pass

class Validator2:

    def __init__(self):
        pass

    def can_validate(self):
        pass

x = MyClass()

obj_1 = None
obj_2 = Validator1()
obj_3 = Validator2()

print(x.my_method_1(obj_1))
print(x.my_method_2(obj_2))
print(x.my_method_3(obj_3))

输出:

None
None
<__main__.Validator2 object at 0x7f6185ca9e10>
None
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