我在list of lists
有两个python
,看起来像这样:
列表1:
[['10001', 'Jason', 'University of Utah School of Medicine'],
['10007', 'Zhang', 'Duke'],
['10016', 'Som', 'Dana-Farber']]
列表2:
[['Som', 'mrcc', 'Wed Dec 20 18:36:28 +0000 2017', '10016'],
['David', 'mrcc', 'Wed Dec 20 18:36:38 +0000 2017', '10013'],
['Kristen', 'mrcc gro', 'Wed Dec 20 18:37:24 +0000 2017', '10045'],
['Zhang', 'wan mrcc', 'Wed Dec 20 18:38:44 +0000 2017', '10007']]
现在我想基于比较这两个excel file
之间的数据将数据写入list of lists
。我的excel文件的结构如下:
为了比较我想要做的是查看list2
中每个列表的最后一个值是否存在于list1
的列表中。因此,对于上面的样本列表,10016
的第一个列表中的list2
存在于list1
中。所以,如果它存在,那么我想在excel行中写下以下值:
[Qazxswpoi,Yes
,value2 from 3rd list of list1
,value 3 in 3rd list oflist1
,value 2 in 1st list oflist2
,value3 in 1st list of list2
]
如果value 1 in 3rd list of list1
中不存在list2
中每个列表的最后一个值,则将以下内容写入excel文件:
[Qazxswpoi,list1
,No
,N/A
,N/A
,value 2 in current list of list2
]
我知道像value3 in current list of list2
中的value 4 in current list of list2
这样的软件包用于写入xlwt
,但我在上面进行这样的比较时无法得到如何编写?
更新:这是我到目前为止所拥有的:
python
当我运行此代码时,它执行没有错误,但当我尝试打开文件时,我得到错误作为excel files
list1和list2是我上面描述的两个列表列表。
你想要做的是直接的,它只是语法和你如何组织代码。以下是我解决问题的方法:
book = xlwt.Workbook(encoding="utf-8")
sheet1 = book.add_sheet("Sheet 1")
sheet1.write(0, 0, "User ID Present?")
sheet1.write(0, 1, "User Name")
sheet1.write(0, 2, "Center Name")
sheet1.write(0, 3, "Text")
sheet1.write(0, 4, "Date")
sheet1.write(0, 5, "User ID")
i=1
for items2 in list2:
for items1 in list1:
if items2[3] in items1[0]:
sheet1.write(i, 0, "Yes")
sheet1.write(i, 1, items1[1])
sheet1.write(i, 2, items1[2])
sheet1.write(i, 3, items2[1])
sheet1.write(i, 4, items2[2])
sheet1.write(i, 5, items1[0])
else:
sheet1.write(i, 0, "No")
sheet1.write(i, 1, 'N/A')
sheet1.write(i, 2, 'N/A')
sheet1.write(i, 3, items2[1])
sheet1.write(i, 4, items2[2])
sheet1.write(i, 5, items2[3])
i=i+1
book.save("Sample_Report_V1.xlsx")
file cannot be opened due to wrong file format or file extension
中。import csv
def merge(list1, list2):
lookup = {row[0]: row for row in list1}
for row2 in list2:
value = row2[-1]
if value in lookup:
row1 = lookup[value]
yield 'Yes', row1[1], row1[2], row2[1], row2[2], row1[0]
else:
yield 'No', 'N/A', 'N/A', row2[1], row2[2], row2[3]
if __name__ == '__main__':
list1 = [
['10001', 'Jason', 'University of Utah School of Medicine'],
['10007', 'Zhang', 'Duke'],
['10016', 'Som', 'Dana-Farber']]
list2 = [
['Som', 'mrcc', 'Wed Dec 20 18:36:28 +0000 2017', '10016'],
['David', 'mrcc', 'Wed Dec 20 18:36:38 +0000 2017', '10013'],
['Kristen', 'mrcc gro', 'Wed Dec 20 18:37:24 +0000 2017', '10045'],
['Zhang', 'wan mrcc', 'Wed Dec 20 18:38:44 +0000 2017', '10007']]
rows = merge(list1, list2)
with open('merge_lists.csv', 'wb') as outfile:
writer = csv.writer(outfile)
writer.writerow(['User ID Present?', 'User Name', 'Center Name',
'Text', 'Date', 'User ID'])
writer.writerows(rows)
的字典,其中用户ID是键,行是值。我的原始答案输出到CSV文件,我认为最容易处理。您可以毫无困难地在Excel中打开该文件。但是,我有一种感觉,你坚持写Excel格式,所以我花了一些时间学习merge
足以使用它。这是我更新的解决方案。请注意,此模块处理较旧的.xls文件格式,而不是较新的.xlsx格式。如果保存为.xlsx,Excel将无法打开它。
lookup