从我的MainActivity我正在使用AccessibilityService在另一个应用程序上执行点击事件,当我打开应用程序并且它显示在屏幕上时,它可以正常工作。但是,我想在不必打开应用程序的情况下执行单击事件,它可以打开但当前不显示在屏幕上。
这可能吗?
public class DiaryAppAccessibilityService extends AccessibilityService {
@Override
protected void onServiceConnected() {
super.onServiceConnected();
}
@Override
public void onAccessibilityEvent (AccessibilityEvent event) {
if (getRootInActiveWindow () == null) {
return;
}
AccessibilityNodeInfoCompat rootInActiveWindow = AccessibilityNodeInfoCompat.wrap (getRootInActiveWindow());
List<AccessibilityNodeInfoCompat> messageNodeList = rootInActiveWindow.findAccessibilityNodeInfosByViewId ("com.diaryapp:id/entry");
if (messageNodeList == null || messageNodeList.isEmpty ()) {
return;
}
AccessibilityNodeInfoCompat messageField = messageNodeList.get (0);
if (messageField.getText () == null || messageField.getText ().length () == 0
|| !messageField.getText ().toString ().endsWith (getApplicationContext ().getString (R.string.diaryapp_suffix))) { // So your service doesn't process any message, but the ones ending your apps suffix
return;
}
List<AccessibilityNodeInfoCompat> sendMessageNodeInfoList = rootInActiveWindow.findAccessibilityNodeInfosByViewId ("com.diaryapp:id/send");
if (sendMessageNodeInfoList == null || sendMessageNodeInfoList.isEmpty ()) {
return;
}
AccessibilityNodeInfoCompat sendMessageButton = sendMessageNodeInfoList.get (0);
// Now fire a click on the send button
sendMessageButton.performAction (AccessibilityNodeInfo.ACTION_CLICK);
@Override
public void onInterrupt() {
}
}
XML配置
<?xml version="1.0" encoding="utf-8"?>
<accessibility-service
xmlns:android="http://schemas.android.com/apk/res/android"
android:accessibilityEventTypes="typeWindowContentChanged"
android:accessibilityFeedbackType="feedbackSpoken"
android:accessibilityFlags="flagDefault"
android:notificationTimeout="100"
android:canRetrieveWindowContent="true"
</accessibility-service>
我删除了这个
android:packageNames="com.diaryapp"
因为我希望该服务在其他应用程序中处于活动状态,并且能够从那里执行click事件。
您尝试做的事情不可能通过设计实现。 Accessibility API旨在帮助残障人士与手机上显示的用户界面进行互动。