滚动视图内的 UIButtons 由于某种原因没有触发其目标功能

问题描述 投票:0回答:1

我已经使用 Xcode 进行编码大约两年了,并且遇到了有关在自定义滚动视图中以编程方式初始化的一系列 UIButton 的问题。无论出于何种原因,当点击时,它们的目标函数

@objc func buttonPressed(_ sender: UITapGestureRecognizer)
不会打印语句“按钮按下!”。我以前从未遇到过这个问题,我希望有人能给我指出正确的方向。我已经包含了所有相关的代码,但如果这还不够,我很乐意发布整个类的代码。

{
    scrollView.frame = CGRect(x: -10, y: bottomView.layer.position.y - 340, width: view.frame.width + 20, height: 200)
    scrollView.backgroundColor = UIColor.black.withAlphaComponent(0.2)
    scrollView.layer.zPosition = 350
    scrollView.layer.borderColor =  UIColor.systemGreen.cgColor
    scrollView.layer.borderWidth = 0.3
    scrollView.isUserInteractionEnabled = true

    let scrollContent = UIView()
    scrollContent.isUserInteractionEnabled = true
    scrollView.isUserInteractionEnabled = true

    let buttonHeight: CGFloat = 70
    let buttonSpacing: CGFloat = 15
    let numberOfButtonsPerRow = 6
    let numberOfRows = 2
    let padding: CGFloat = 20

    for row in 0..<numberOfRows {
        for col in 0..<numberOfButtonsPerRow {
            let button = UIButton()
          
            button.frame = CGRect(x: padding + CGFloat(col) * (buttonHeight + buttonSpacing),
                                  y: padding + CGFloat(row) * (buttonHeight + buttonSpacing),
                                  width: buttonHeight,
                                  height: buttonHeight)
        
            button.setTitleColor(.white, for: .normal)
            button.backgroundColor = .black
            button.layer.zPosition = 500
            button.isUserInteractionEnabled = true
          
            button.layer.borderColor =  UIColor.systemGreen.cgColor
            button.layer.borderWidth = 0.75
            button.layer.cornerRadius = 10
          
            button.isUserInteractionEnabled = true

            let tapGesture = UITapGestureRecognizer(target: self, action: #selector(buttonPressed(_:)))
                  button.addGestureRecognizer(tapGesture)
         
            let imageName = buttonImages[row * numberOfButtonsPerRow + col]
                  
            button.setImage(UIImage(named: imageName)?.withRenderingMode(.alwaysOriginal), for: .normal)
            scrollContent.addSubview(button)
            scrollContent.isUserInteractionEnabled = true
        }
    }

    let contentWidth = padding + CGFloat(numberOfButtonsPerRow) * (buttonHeight + buttonSpacing)
    let contentHeight = padding + CGFloat(numberOfRows) * (buttonHeight + buttonSpacing)
 
    scrollView.contentSize = CGSize(width: contentWidth, height: contentHeight)
 
    scrollView.addSubview(scrollContent)
     
    view.addSubview(scrollView)
}

@objc func buttonPressed(_ sender: UITapGestureRecognizer) {
    print("Button pressed!")
}
ios swift uiscrollview uibutton
1个回答
0
投票

按钮不会“触发其目标功能”,因为您没有点击按钮,即使您可能认为是这样。

您无法与“超出其超级视图(或该视图的超级视图,以及链上游)边界”的 UI 元素进行交互。 将此行添加到您的代码中:

scrollContent.clipsToBounds = true

并运行应用程序。现在,您甚至不会

看到任何按钮。 您必须为

scrollContent

提供包含按钮的宽度和高度。

您可以让按钮与此行一起使用:

// give scrollContent a width and height that fits the buttons scrollContent.frame.size = .init(width: contentWidth, height: contentHeight)

快速提示:在开发过程中,为所有 UI 元素提供对比背景颜色,以便您可以轻松看到框架。

scrollContent.backgroundColor = .yellow

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