如何在post nodejs中的formdata中获得额外的表单字段

Question

name之类的键值对被附加到客户端XMLHttpRequest中的表单数据中，并与要上传的文件一起发送。

如何使用Node.js在服务器端提取这些值。

浏览器：

formdata = new FormData();
for( var x = 0;x < files.length;x = x+1){
    formdata.append('file',files[x]);
}
formdata.append('name',name);  //name appended here to formdata
formdata.append('email',email);
formdata.append('reason',reason);
formdata.append('location',location);
var xhr = new XMLHttpRequest();
var url = "/sign_8081";
xhr.open("POST" ,url);
xhr.withCredentials = true;

Node.js服务器：

router.post('/sign_8081', (req, res) => {
    console.log("sign 8081called"+JSON.stringify(req.body))
    console.log(req.query.name);
    console.log(req.body.name); //want name key value in nodejs code 
    let body = '';
    var rb;
    req.on('data', chunk => {
        body += chunk.toString(); // convert Buffer to string
    });
    req.on('end', () => {      
        rb = parse(body)
        console.log(rb.name);
    });
    console.log(req.file.filename)
    res.send(req.file.filename)                
});

Answer 1

[如果使用的是expressjs，则使用正文解析中间件，例如express.json()或express.urlencoded()，则可以访问表单输入req.body。

   var app = express()

   app.use(express.json()) // for parsing application/json
   app.use(express.urlencoded({ extended: true })) // for parsing application/x-   www-form-urlencoded

    router.post('/sign_8081', (req, res) => {
    console.log("sign 8081called"+JSON.stringify(req.body))
    console.log(req.query.name);// do not use this
    console.log(req.body); // object of inputs
    let body = '';
    var rb;
    req.on('data', chunk => {
        body += chunk.toString(); // convert Buffer to string
    });
    req.on('end', () => {      
        rb = parse(body)
        console.log(rb.name);
    });
    console.log(req.file.filename)
    res.send(req.file.filename)                
});

有关expressjs请求对象expressjs docs的更多信息>