如何计算上限文件中有效WPA握手的数量

Question

我想知道封顶文件中有多少有效的WPA握手。

我尝试过使用这种方法：

  tshark -r file.cap -R "(wlan.fc.type_subtype == 0x08 || wlan.fc.type_subtype == 0x05 || eapol)" -2 


   1   0.064507 D-LinkIn_89:9f:44 → Broadcast    802.11 325 Beacon frame, SN=2485, FN=0, Flags=........, BI=100, SSID=AAAAA
   2  15.639995 LgElectr_94:af:ba → D-LinkIn_89:9f:44 EAPOL 155 Key (Message 2 of 4)
   3  15.643065 D-LinkIn_89:9f:44 → LgElectr_94:af:ba EAPOL 213 Key (Message 3 of 4)
   4  27.695798 LgElectr_94:af:ba → D-LinkIn_89:9f:44 EAPOL 155 Key (Message 2 of 4)
   5  27.703480 LgElectr_94:af:ba → D-LinkIn_89:9f:44 EAPOL 133 Key (Message 4 of 4)
   6  54.926712 D-LinkIn_89:9f:44 → LgElectr_94:af:ba EAPOL 133 Key (Message 1 of 4)
   7  54.975420 D-LinkIn_89:9f:44 → LgElectr_94:af:ba EAPOL 213 Key (Message 3 of 4)
   8  81.340985 D-LinkIn_89:9f:44 → LgElectr_94:af:ba EAPOL 133 Key (Message 1 of 4)
   9  81.351228 LgElectr_94:af:ba → D-LinkIn_89:9f:44 EAPOL 155 Key (Message 2 of 4)
  10  81.353779 D-LinkIn_89:9f:44 → LgElectr_94:af:ba EAPOL 213 Key (Message 3 of 4)
  11  81.358911 LgElectr_94:af:ba → D-LinkIn_89:9f:44 EAPOL 133 Key (Message 4 of 4)
  12 119.080377 LgElectr_94:af:ba → D-LinkIn_89:9f:44 EAPOL 133 Key (Message 4 of 4)

我想要以下输出：

count.sh file.cap

3（3次有效握手）。

我想知道封顶文件中有多少有效的WPA握手。

我尝试过使用这种方法：

  tshark -r file.cap -R "(wlan.fc.type_subtype == 0x08 || wlan.fc.type_subtype == 0x05 || eapol)" -2 


   1   0.064507 D-LinkIn_89:9f:44 → Broadcast    802.11 325 Beacon frame, SN=2485, FN=0, Flags=........, BI=100, SSID=AAAAA
   2  15.639995 LgElectr_94:af:ba → D-LinkIn_89:9f:44 EAPOL 155 Key (Message 2 of 4)
   3  15.643065 D-LinkIn_89:9f:44 → LgElectr_94:af:ba EAPOL 213 Key (Message 3 of 4)
   4  27.695798 LgElectr_94:af:ba → D-LinkIn_89:9f:44 EAPOL 155 Key (Message 2 of 4)
   5  27.703480 LgElectr_94:af:ba → D-LinkIn_89:9f:44 EAPOL 133 Key (Message 4 of 4)
   6  54.926712 D-LinkIn_89:9f:44 → LgElectr_94:af:ba EAPOL 133 Key (Message 1 of 4)
   7  54.975420 D-LinkIn_89:9f:44 → LgElectr_94:af:ba EAPOL 213 Key (Message 3 of 4)
   8  81.340985 D-LinkIn_89:9f:44 → LgElectr_94:af:ba EAPOL 133 Key (Message 1 of 4)
   9  81.351228 LgElectr_94:af:ba → D-LinkIn_89:9f:44 EAPOL 155 Key (Message 2 of 4)
  10  81.353779 D-LinkIn_89:9f:44 → LgElectr_94:af:ba EAPOL 213 Key (Message 3 of 4)
  11  81.358911 LgElectr_94:af:ba → D-LinkIn_89:9f:44 EAPOL 133 Key (Message 4 of 4)
  12 119.080377 LgElectr_94:af:ba → D-LinkIn_89:9f:44 EAPOL 133 Key (Message 4 of 4)

我想要以下输出：

count.sh file.cap

3（3次有效握手）。

我不知道的是确定何时一组消息是有效的握手来破解它（让我们说像aircrack-ng这样的东西）。

救命。

Answer 1

好吧，经过一些挖掘，我意识到答案就在眼前。

我发现LazyScript（github repo）具有检查/验证WPA / WPA2握手的功能。潜入源代码我发现它使用Pyrit和Cowpatty

总而言之，有一种非常简单/简单的方法来计算封面文件中的握手（也检查质量）：

pyrit -r fileWithHandShakes.cap analyze

它会给出这个输出：

Pyrit 0.4.0 (C) 2008-2011 Lukas Lueg http://pyrit.googlecode.com
This code is distributed under the GNU General Public License v3+

Parsing file '/folder/fileWithHandShakes.cap' (1/1)...
Parsed 112 packets (112 802.11-packets), got 1 AP(s)

#1: AccessPoint fd:94:e3:43:bc:b6 ('MyWifi'):
  #1: Station 30:fd:38:c1:2b:bb, 3 handshake(s):
    #1: HMAC_SHA1_AES, good, spread 1
    #2: HMAC_SHA1_AES, bad, spread 17
    #3: HMAC_SHA1_AES, bad, spread 22
  #2: Station 44:00:10:06:bc:bc, 2 handshake(s):
    #1: HMAC_SHA1_AES, good, spread 1
    #2: HMAC_SHA1_AES, bad, spread 3

这是计算握手的方式，也是检查握手质量的方法。