如何在maya中查询当前视口渲染器

Question

任何人都有一个很好的解决方案来查询python中当前的maya视口渲染器（Viewport 2.0，默认视口，高质量视口）？

Answer 1

@Tomek的答案将完美无缺。如果你要去PyMEL路线，你可以这样做：

import pymel.core.uitypes as pmui

model_panel = pmui.ModelEditor(pm.getPanel(withFocus=True))
print pmui.ModelEditor.getRendererName(model_panel)

虽然，那个片段似乎很有气质。它有时会抛出一个错误，抱怨没有找到模型编辑器，特别是从架子上执行时。

另一种方式有点罗嗦，但它每次都有效：

import pymel.core as pm
import pymel.core.uitypes as pmui

modelPanelList = []
modelEditorList = pm.lsUI(editors=True)
for myModelPanel in modelEditorList:
    if myModelPanel.find('modelPanel') != -1:
        modelPanelList.append(myModelPanel)

for modelPanel in modelPanelList:    
    if pmui.ModelEditor(modelPanel).getActiveView():
        try:
            # Always better to try in the case of active panel operations
            # as the active panel might not be a viewport.
            print pmui.ModelEditor(modelPanel).getRendererName()
        except Exception as e:
            # Handle exception
            print e

一个简洁的伪PyMEL方式就是PyMEL-ify Tomek的答案：

import pymel.core as pm
print pm.modelEditor(pm.getPanel(wf=True), q=True, rnm=True)

要获取视口渲染器列表：

import pymel.core.uitypes as pmui
print pmui.ModelEditor().getRendererList()

以下是模型编辑器和视口渲染器的一些额外信息。获得他们“友好”的名字：

import pymel.core.uitypes as pmui
print pmui.ModelEditor().getRendererListUI()

简单地说，设置它们，我会使用PyMEL并执行：

import pymel.core.uitypes as pmui

# assuming you know which modelPanel you want to affect
pmui.ModelEditor("modelPanel4").setRendererName("ogsRenderer")

要影响所有视口（modelPanels），我会这样做：

import pymel.core as pm
import pymel.core.uitypes as pmui

modelPanelList = []
modelEditorList = pm.lsUI(editors=True)
for myModelPanel in modelEditorList:
    if myModelPanel.find('modelPanel') != -1:
        modelPanelList.append(myModelPanel)

for modelPanel in modelPanelList:
    pmui.ModelEditor(modelPanel).setRendererName("ogsRenderer")

仅影响焦点视口：

import pymel.core as pm
import pymel.core.uitypes as pmui

modelPanelList = []
modelEditorList = pm.lsUI(editors=True)
for myModelPanel in modelEditorList:
    if myModelPanel.find('modelPanel') != -1:
        modelPanelList.append(myModelPanel)

for modelPanel in modelPanelList:    
    if pmui.ModelEditor(modelPanel).getActiveView():
        try:
            # Always better to try in the case of active panel operations
            # as the active panel might not be a viewport.
            pmui.ModelEditor(modelPanel).setRendererName("ogsRenderer")
        except Exception as e:
            # Handle exception
            print e

Answer 2

此脚本返回焦点面板的渲染器：

import maya.cmds as cmds

print cmds.modelEditor( cmds.getPanel(wf=True), q=True, rnm=True )

Answer 3

迭代所有modelPanel，找到一个活动的（灰色轮廓）并要求rendereName（rnm）

梅尔：

// find current modelEditor
string $cur_mp;
for ($mp in `getPanel -typ "modelPanel"`){
    // check if active
    if (`modelEditor -q -av $mp`){
        $cur_mp = $mp;
        break;
    }
}

if ($cur_mp != ""){
    // your coude next
    print $cur_mp;
    $new_rndr = "ogsRenderer";
    // set new renderer
    modelEditor -e -rnm $new_rndr $cur_mp;
}

潘岳：

import maya.cmds as cm

cur_mp = None
for mp in cm.getPanel(type="modelPanel"):
    if cm.modelEditor(mp, q=1, av=1):
        cur_mp = mp
        break

if cur_mp:
    # do your stuff
    print cur_mp
    new_rndr = "ogsRenderer"
    cm.modelEditor(cur_mp, e=1, rnm=new_rndr)

pymel：

import pymel.core as pm

# maybe its not the best solution to iterate over all existing modelPanels
mp_ls = [x
         for x in pm.lsUI() 
         if type(x).__name__ == "ModelEditor"
         and type(x.getParent()).__name__ == "PyUI"
         and x.getActiveView()]

if mp_ls:
    # do your stuff
    print mp_ls[0]    # current modelEditor
    new_rndr = "ogsRenderer"
    mp_ls[0].setRendererName(new_rndr)