对C#类的Soap响应总是返回空值。

Question

我很难从web服务解析soap响应并将其转换为c#对象。无论我做什么，它总是返回空元素。这是我的响应。

<soapenv:Envelope xmlns:soapenv='http://schemas.xmlsoap.org/soap/envelope/' 
 xmlns:tem='http://tempuri.org/'>
 <soapenv:Header/> <soapenv:Body>
 <tem:Response><tem:Result>
  <RETN>108</RETN><DESC> This is an error</DESC></tem:Result></tem:Response>
   </soapenv:Body>
 </soapenv:Envelope>

这是我如何解析这个响应。

var xDoc = XDocument.Parse(response);
var xLoginResult = xDoc.Root.Descendants().FirstOrDefault(d => d.Name.LocalName.Equals("Result"));
var serializer = new XmlSerializer(typeof(Result));
using (var reader = xLoginResult.CreateReader())
{
    var convertedResonse= (Result)serializer.Deserialize(reader);
    // inside this convertedResonse RETN and  DESC is alway null
}

这里是我的结果类

   [XmlRoot(ElementName = "Result", Namespace = "http://tempuri.org/")]
    public class Result
    {
        [XmlElement("RETN")]
        public string RETN { get; set; }
        [XmlElement("DESC")]
        public string DESC { get; set; }
    }

    [XmlRoot(ElementName = "Response", Namespace = "http://tempuri.org/")]
    public class Response
    {
        [XmlElement(ElementName = "Result", Namespace = "http://tempuri.org/")]
        public Result Result { get; set; }
    }

    [XmlRoot(ElementName = "Body", Namespace = "http://schemas.xmlsoap.org/soap/envelope/")]
    public class Body
    {
        [XmlElement(ElementName = "Response", Namespace = "http://tempuri.org/")]
        public Response Response { get; set; }
    }

    [XmlRoot(ElementName = "Envelope", Namespace = "http://schemas.xmlsoap.org/soap/envelope/")]
    public class Envelope
    {
        [XmlElement(ElementName = "Header", Namespace = "http://schemas.xmlsoap.org/soap/envelope/")]
        public string Header { get; set; }
        [XmlElement(ElementName = "Body", Namespace = "http://schemas.xmlsoap.org/soap/envelope/")]
        public Body Body { get; set; }
        [XmlAttribute(AttributeName = "soapenv", Namespace = "http://www.w3.org/2000/xmlns/")]
        public string Soapenv { get; set; }
        [XmlAttribute(AttributeName = "tem", Namespace = "http://www.w3.org/2000/xmlns/")]
        public string Tem { get; set; }
    }

内部价值 convertedResonse 始终是空的。任何想法将是非常感激？

Answer 1

对于 Xml 问题中发布的，你不需要使用 XmlSerializer，只是 XDocument 借用 Linq to Xml 就足够了，就像下面的代码一样。

1-创建NameSpace。

XNamespace xn = "http://tempuri.org/";

2 - 将XDocument的查询改编为.XDocument。

Result result = xDoc
    .Descendants(xn + "Result")
    .Select(x => new Result { DESC = x.Element("DESC").Value, RETN = x.Element("RETN").Value })
    .FirstOrDefault();

Console.WriteLine($"DESC:{result.DESC}, RETN:{result.RETN}");

结果

DESC: This is an error, RETN:108

希望对您有所帮助。