谁能告诉我python-crontab我在做什么错?
from crontab import CronTab
system_cron = CronTab()
产生以下错误:
File "test.py", line 3, in <module>
cron = CronTab()
TypeError: __init__() takes exactly 2 arguments (1 given)
[我直接从包装说明中尝试其他示例变体时遇到相同的问题:
my_user_cron = CronTab(user=True)
users_cron = CronTab(user='username')
我也尝试过使用这种方法创建对象,该方法在python-crontab.py文件中找到:
cron = CronTab(tab='')
但是它会产生此错误:TypeError: __init__() got an unexpected keyword argument 'tab'
我尝试查看软件包中的代码,看是否可能是文档错误,并想出了解决方法,但这超出了我的技术水平。我相信这是定义我应该如何创建crontab对象的代码:
def __init__(self, user=None, tab=None, tabfile=None, log=None):
if user == True and not WINOS:
user = pwd.getpwuid( os.getuid() )[ 0 ]
self.lines = None
self.crons = None
self.filen = None
# Protect windows users
self.root = not WINOS and os.getuid() == 0
self.user = user
# Detect older unixes and help them out.
self.intab = tab
self.read(tabfile)
self._log = log
对我在做什么错有任何想法吗?
help(CronTab)返回:
class CronTab(__builtin__.object)
| Methods defined here:
|
| __init__(self, crontab)
|
| next(self, now=None, increments=[<function <lambda>>, <function <lambda>>, <function <lambda>>, <function _month_incr>, <function <lambda>>, <function _year_incr>, <function <lambda>>, <function <lambda>>, <function <lambda>>, <function <lambda>>, <function <lambda>>], delta=True)
| How long to wait in seconds before this crontab entry can next be
| executed.
|
| previous(self, now=None, delta=True)
|
| test(self, entry)
|
| ----------------------------------------------------------------------
| Data descriptors defined here:
|
| matchers