用STL()分解xts时间序列

问题描述 投票:1回答:1

我试图分解xts时间序列并创建一个包含2列的数据框。

  1. 观察日期
  2. 分解时间序列的趋势值

基础数据框具有以下结构:

Date        x     y        z
2016-01-01 40419.35 12595 3.20
2016-01-02 44283.35 13904 3.18
2016-01-03 36277.23 10355 3.50
2016-01-04 42545.05 11929 3.56
2016-01-05 42402.22 13737 3.08
2016-01-06 49919.22 13661 3.65
...
2018-12-30 48719.22 13563 3.65
2018-12-31 49919.22 13661 3.65

这是我到目前为止所做的。

#1. Creating an xts object with weekly frequency
TimeSeries <- xts(x=Data[,-1],order.by=as.Date(Data$Date,"%Y/%m/%d")) 
TimeSeriesWeekly <- period.apply(TimeSeriesWeekly, INDEX = endpoints(TimeSeriesWeekly, on = "weeks"), FUN = colSums) 
attr(TimeSeriesWeekly, 'frequency') <-52
TimeSeriesWeekly<-TimeSeriesWeekly[,1] #keeping only the X variable I want to decompose

#2. Converting to a TS object in order to apply stl() decomposition formula
TimeSeriesWeekly <- ts(TimeSeriesWeekly[,1],frequency=52)

#3. Decomposing the TS object and distilling the trend
TimeSeriesWeeklyDecomposed<-stl(TimeSeriesWeekly, s.window="periodic")
TimeSeriesWeeklyTrend     <- as.data.frame(TimeSeriesWeeklyDecomposed$time.series[,2])

我的问题是TimeSeriesWeeklyTrend数据框不包含日期变量。我怎么能通过呢?

r xts forecasting
1个回答
0
投票

解决了以下代码的问题:

#2. Converting to a TS object in order to apply stl() decomposition formula
ts_data  <- ts(as.numeric(TimeSeriesWeekly[,1]),frequency=52)

#3. Decomposing the TS object with STL()
TimeSeriesWeeklyDecomposed<-stl(ts_data , s.window="periodic")

#4 Appending it to the initial xts object
TimeSeriesWeekly <- merge(TimeSeriesWeekly,TimeSeriesWeeklyDecomposed$time.series[,2])
names(TimeSeriesWeekly)[ncol(TimeSeriesWeekly)]<-"Trend" 
© www.soinside.com 2019 - 2024. All rights reserved.