为Vaadin-Application构建多个工件[Gradle]

Question

我目前正在使用gradle vaadin-plugin处理Vaadin 8项目。

在该项目中有3个SourceSets main，a和b。后两者排除了一些视图和功能。是否可以通过gradle one为每个sourceSet构建3个Artifcats。我尝试修改战争任务，但这打破了观点。

conf{
    aCompile.extendsFrom compile
    aRuntime.extendsFrom runtime

    bCompile.extendsFrom compile
    bRuntime.extendsFrom runtime
}
 sourceSets {
    main {
        java {
            srcDirs = ['src/main/java', 'src/main/generated']
        }
    }
    a{
        java {
            srcDirs = ['src/main/java', 'src/main/generated']
            exclude 'com/exmaple/features/b'
            exclude 'com/exmaple/views/b'
        }

        compileClasspath += main.output
        runtimeClasspath += main.output

        output.resourcesDir = 'build/resources/main'
        output.classesDir = 'build/classes/java/main'
    }
    b{
        java {
            srcDirs = ['src/main/java', 'src/main/generated']
            exclude 'com/exmaple/features/a'
            exclude 'com/exmaple/views/a'
        }
        compileClasspath += main.output
        runtimeClasspath += main.output

        output.resourcesDir = 'build/resources/main'
        output.classesDir = 'build/classes/java/main'
    }
}
task aWar(type: War) {
    appendix = "a"
    from sourceSets.a.output
}

task bWar(type: War) {
    appendix = "b"
    from sourceSets.b.output
}

Answer 1

从https://docs.gradle.org/current/userguide/artifact_management.html#sec:declaring_artifacts你应该能够为每个源集声明一个工件。

在你的情况下，它看起来像这样：

task aWar(type: War, dependsOn: classes) {
  baseName = 'a.war'
  classpath = project.configurations.aRuntime
}

task bWar(type: War, dependsOn: classes) {
  baseName = 'b.war'
  classpath = project.configurations.bRuntime
}

artifacts {
   archives aWar, bWar
}

WAR任务还允许您使用正则表达式包含/排除类。在https://docs.gradle.org/current/dsl/org.gradle.api.tasks.bundling.War.html了解更多