Spring cron 表达式 - 如何获取最后执行时间

Question

在 Spring 中，我可以使用以下方法获取下一个执行时间：

final CronSequenceGenerator generator = new CronSequenceGenerator(cronExpression);
final Date nextExecutionDate = generator.next(new Date());

但是如何从 cron 表达式中获取最后执行时间呢？

Answer 1

它使用二分查找来查找最后执行时间。

import static org.junit.jupiter.api.Assertions.assertEquals;
import static org.junit.jupiter.api.Assertions.assertNotNull;

import java.time.Duration;
import java.time.ZonedDateTime;
import java.util.Objects;
import java.util.concurrent.TimeUnit;
import org.junit.jupiter.api.Test;
import org.springframework.scheduling.support.CronExpression;

public class CronTest {

    @Test
    void cronTest() {
        CronExpression expression = CronExpression.parse("1 0/10 * * * ?");
        ZonedDateTime nextTime = expression.next(ZonedDateTime.now());
        assertNotNull(nextTime);
        ZonedDateTime prevTime = getPrevTime(expression, nextTime, nextTime.minusDays(1));
        assertEquals(nextTime.minusMinutes(10), prevTime);
    }

    private ZonedDateTime getPrevTime(CronExpression expression, ZonedDateTime nextTime, ZonedDateTime mayPrevTime) {
        ZonedDateTime start = mayPrevTime;
        ZonedDateTime end = nextTime;
        while (start.isBefore(end)) {
            ZonedDateTime middle = end.minusSeconds(
                TimeUnit.MILLISECONDS.toSeconds(Duration.between(start, end).toMillis() / 2));
            ZonedDateTime tmpNextTime = expression.next(middle);
            if (Objects.equals(tmpNextTime, nextTime)) {
                end = middle.minusSeconds(1);
            } else {
                start = middle.plusSeconds(1);
            }
        }
        return start;
    }
}

Answer 2

尝试一下

import org.springframework.scheduling.support.CronSequenceGenerator;
        final Date now = new Date();
        // 获取上一次执行时间
        CronSequenceGenerator cronSequenceGenerator = new CronSequenceGenerator("0 0/5 * * * ? ");
        // 获取下一次执行时间
        final Date next = cronSequenceGenerator.next(now);
        // 差值
        final long diff = next.getTime() - now.getTime();
        final Date last = new Date(now.getTime() - diff);