如何以python打开.mpg格式的视频

Question

我正在以.mpg格式对我的视频进行对象跟踪，我正在使用OpenCV跟踪对象，但是在我的代码中打开它时我遇到了一些问题，我已经附加了我的代码。

import cv2
import sys

(major_ver, minor_ver, subminor_ver) = (cv2.__version__).split('.')

if __name__ == '__main__' :

    # Set up tracker.
    # Instead of MIL, you can also use

    tracker_types = ['BOOSTING', 'MIL','KCF', 'TLD', 'MEDIANFLOW', 'GOTURN', 'MOSSE', 'CSRT']
    tracker_type = tracker_types[1]
    print(tracker_type)



    if tracker_type == 'MIL':
            tracker = cv2.TrackerMIL_create()


    # Read video
    video = cv2.VideoCapture("Stroll.mpg")

    # Exit if video not opened.
    if not video.isOpened():
        print ("Could not open video")
        sys.exit()

    # Read first frame.
    ok, frame = video.read()
    if not ok:
        print ('Cannot read video file')
        sys.exit()

    # Define an initial bounding box
    bbox = (287, 23, 86, 320)

    # Uncomment the line below to select a different bounding box
    bbox = cv2.selectROI(frame, False)

    # Initialize tracker with first frame and bounding box
    ok = tracker.init(frame, bbox)

    while True:
        # Read a new frame
        ok, frame = video.read()
        if not ok:
            break

        # Start timer
        timer = cv2.getTickCount()

        # Update tracker
        ok, bbox = tracker.update(frame)

        # Calculate Frames per second (FPS)
        fps = cv2.getTickFrequency() / (cv2.getTickCount() - timer)

        # Draw bounding box
        if ok:
            # Tracking success
            p1 = (int(bbox[0]), int(bbox[1]))
            p2 = (int(bbox[0] + bbox[2]), int(bbox[1] + bbox[3]))
            cv2.rectangle(frame, p1, p2, (255,0,0), 2, 1)
        else :
            # Tracking failure
            cv2.putText(frame, "Tracking failure detected", (100,80), cv2.FONT_HERSHEY_SIMPLEX, 0.75,(0,0,255),2)

        # Display tracker type on frame
        cv2.putText(frame, tracker_type + " Tracker", (100,20), cv2.FONT_HERSHEY_SIMPLEX, 0.75, (50,170,50),2)

        # Display FPS on frame
        cv2.putText(frame, "FPS : " + str(int(fps)), (100,50), cv2.FONT_HERSHEY_SIMPLEX, 0.75, (50,170,50), 2)

        # Display result
        cv2.imshow("Tracking", frame)

        # Exit if ESC pressed
        k = cv2.waitKey(1) & 0xff
        if k == 27 : break

但是我在这里面临的错误是：-

Could not open video
[ERROR:0] global C:\projects\opencv-python\opencv\modules\videoio\src\cap.cpp
(116) cv::VideoCapture::open VIDEOIO(CV_IMAGES): raised OpenCV exception:

OpenCV(4.1.2) C:\projects\opencv-python\opencv\modules\videoio
\src\cap_images.cpp:253: error: (-5:Bad argument) CAP_IMAGES: can't find
starting number (in the name of file): Stroll.mpg in function 'cv::icvExtractPattern'

我正在使用python 3.6.8OpenCV版本4.1.2

Answer 1

可能错误的路径检查Stroll.mpg是否在您的工作目录中。如果是，请尝试播放.mp4视频。路径很可能错误或文件名拼写错误。参考：https://answers.opencv.org/question/1965/cv2videocapture-cannot-read-from-file/