我想将bash变量中的String转换为Java Supported String样式。
例如:data="{"5": ">10%", "4": "<5%", "3": ">28 months", "2": "20%", "1": 100}"
作为echo $data
给我这个结果:
"{\n" +
" \"1\": 21,\n" +
" \"2\": \"40%\",\n" +
" \"3\": \"<24 months\",\n" +
" \"4\": \"<5%\",\n" +
" \"5\": \">10%\"\n" +
"}"
但是我还需要使用echo "String data = $data;" >> file.txt
将这个值传递到一个文件中,其中数据是处理后的值,它会抛出奇怪的结果
String data = "{
" +
" \"5\": \">10%\",
" +
" \"4\": \"<5%\",
" +
" \"3\": \">28 months\",
" +
" \"2\": \"20%\",
" +
" \"1\": 100
" +
"}";
但预计是:
String data = "{\n" +
" \"1\": 50,\n" +
" \"2\": \"40%\",\n" +
" \"3\": \">28 months\",\n" +
" \"4\": \"<5%\",\n" +
" \"5\": \">10%\"\n" +
"}";
使用一个伟大的adhoc
方法:(两次调用perl)
data='{"5": ">10%", "4": "<5%", "3": ">28 months", "2": "20%", "1": 100}'
echo $data |\
perl -pe 's/{/{\n/; s/}/\n}/; s/, /,\n/g; s/^"/ "/gm' |\
perl -0pe 's/"/\\"/g; s/\n/\\n" + \n/g; s/^/"/gm; s/\}\\n.*$/}"/'
结果是:
"{\n" +
" \"5\": \">10%\",\n" +
" \"4\": \"<5%\",\n" +
" \"3\": \">28 months\",\n" +
" \"2\": \"20%\",\n" +
" \"1\": 100\n" +
"}"
进一步测试:
test='{"first" : "1st", "second": "2nd", "third" : "3rd" }'
echo $test |\
perl -pe 's/{/{\n/; s/}/\n}/; s/, /,\n/g; s/^"/ "/gm' |\
perl -0pe 's/"/\\"/g; s/\n/\\n" + \n/g; s/^/"/gm; s/\}\\n.*$/}"/'
回报
"{\n" +
" \"first\" : \"1st\",\n" +
" \"second\": \"2nd\",\n" +
" \"third\" : \"3rd\" \n" +
"}"
至于输出这个新字符串,请尝试:
data='{"5": ">10%", "4": "<5%", "3": ">28 months", "2": "20%", "1": 100}'
newdata=$(echo $data |\
perl -pe 's/{/{\n/; s/}/\n}/; s/, /,\n/g; s/^"/ "/gm' |\
perl -0pe 's/"/\\"/g; s/\n/\\n" + \n/g; s/^/"/gm; s/\}\\n.*$/}"/')
echo "String data = $newdata" >> /tmp/file.txt
至于更新(*使用sh
而不是bash
,获得2个\t
s *),请尝试以下(它变得更丑陋和丑陋......):
data='{"5": ">10%", "4": "<5%", "3": ">28 months", "2": "20%", "1": 100}'
newdata=$(echo $data |\
perl -pe 's/{/{\n/; s/}/\n}/; s/, /,\n/g; ' |\
perl -0pe 's/"/\\"/g; s/\n/\\n" + \n/g; s/^/"/gm; s/^"/\t\t"/gm; s/^\t\t"/"/; s/\}\\n.*$/}"/')
/bin/echo "String data = $newdata" >> /tmp/file.txt