PCA,同时保留R中的行顺序

问题描述 投票:0回答:1

我想使用prcomp对前两列中具有重复因子,后跟数值向量的数据集进行PCA分析:

Genus1  Species1    6.320000    8.720000    6.420000
Genus2  Species2    8.430000    11.780000   4.490000
Genus2  Species2    8.310000    10.940000   4.180000
Genus3  Species3    9.290000    13.060000   5.990000
Genus3  Species3    8.960000    13.320000   6.36000

如何将这个数据集转换为正确的格式以与prcomp一起运行,以使PC得分与原始数据集的顺序相同?

r pca
1个回答
0
投票

假设您的数据是:

x = structure(list(V1 = structure(c(1L, 2L, 2L, 3L, 3L), .Label = c("Genus1", 
"Genus2", "Genus3"), class = "factor"), V2 = structure(c(1L, 
2L, 2L, 3L, 3L), .Label = c("Species1", "Species2", "Species3"
), class = "factor"), V3 = c(6.32, 8.43, 8.31, 9.29, 8.96), V4 = c(8.72, 
11.78, 10.94, 13.06, 13.32), V5 = c(6.42, 4.49, 4.18, 5.99, 6.36
)), class = "data.frame", row.names = c(NA, -5L))

无论如何,您都无法通过因素进行pca,因此:

pca = prcomp(x[,3:5])
pca_scores = cbind(x[,1:2],pca$x)
pca_scores
      V1       V2        PC1        PC2          PC3
1 Genus1 Species1 -3.4571239  0.8812539  0.003197962
2 Genus2 Species2  0.2914003 -0.9790128 -0.165842662
3 Genus2 Species2 -0.4813849 -1.3641274  0.099844800
4 Genus3 Species3  1.8024971  0.5080058  0.199344981
5 Genus3 Species3  1.8446114  0.9538805 -0.136545080
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