获取最后 n 个柱的轴心点

Question

if barstate.islast
// Loop through the last 1000 bars
    for i = 0 to 1000
        float _pivotHigh = na
        int _leftBars = 10
        int _rightBars = 10
        int _pivotRange = ( _leftBars + _rightBars )
        float _leftEdgeValue = nz(_series[_pivotRange], na)
        if not na(_series) and _leftBars > 0 and _rightBars > 0 and not na(_leftEdgeValue)
            float _possiblePivotHigh = _series[_rightBars]
            float[] _arrayOfSeriesValues = array.new_float(0)
            for _barIndex = _pivotRange to 0
                array.push(_arrayOfSeriesValues, _series[_barIndex])
            //end for
            int _pivotHighRightBars = array.size(_arrayOfSeriesValues) - array.lastindexof(_arrayOfSeriesValues, array.max(_arrayOfSeriesValues)) - 1
            _pivotHigh := ( _pivotHighRightBars == _rightBars ) ? _possiblePivotHigh : na
        
// Plot the label when a pivot point is detected. (Nothing gets plotted)
        if not na(_pivotHigh)
            label.new(bar_index[_leftBars], _pivotHigh, text=str.tostring(_pivotHigh))

当我们到达图表的末尾时，将实施一个回顾循环以遍历最后 1000 个柱，并且需要绘制和标记该时期的枢轴点。目前，没有任何计划。