Python：集成 100 个函数和集成变量

Question

我想计算以下形式的积分：。

我正在努力用Python实现这个。有没有一种程序化的方法来实现这一点？我尝试用几个 for 循环来执行此操作，但我陷入了错误

SystemError: too many statically nested blocks

。

fs = {}
for i in range(100):
   fs[i] = lamda x: x*i

for x1 in np.arange(0,1,.01):
   for x2 in np.arange(0,1,.01):
      ....
          for x100 in np.arange(0,1,.01):
             for i in range(100):
                exec("summ+= fs[i](x%i"%i)

Answer 1

当然很慢： “for i in range(100)”(1)部分达到100 * 100 * 100 * ... * 100 (100 '*100's) = 100 ^ 100;人们说 n^2 不好...... 无论如何，我会这样做：

- Put 100 values initialized with 0 into a list.
 - for i = 0 to 100 ^ 100:
   - go through the list and use the k-th value as the parameter for the k-th function. do the summing thing
   - Add 0.1 to the n-th value in the list; 
     if this value is now == 1; set it to 0 and go to the (n+1)-th value and repeat this procedure until you reach the end of the list or one value is < 1. 
     Start with the first value in the list.
now you have your sum.