已经注册了一个副本：org.hibernate.query.sqm.tree.select.SqmSubQuery。下面的代码出现此错误，如何修复它

Question

    public static<T> Long getRows(final EntityManager em, final CriteriaQuery<T> criteria) {
        final CriteriaBuilder cb = em.getCriteriaBuilder();
        final CriteriaQuery<Long> countCriteria = cb.createQuery(Long.class);
        final Root<T> root = countCriteria.from(cb.getResultType());
        countCriteria.select(cb.count(root));

        for(final Root<?> rootObj: criteria.getRoots()){
            countCriteria.getRoots().add(rootObj);
        }
        
        final Predicate whereRes = criteria.getRestriction();
        if(whereRes != null){
            countCriteria.where(whereRes);
        }

        final Predicate groupRes = criteria.getGroupRestriction();
        if(groupRes != null){
            countCriteria.having(groupRes);
        }
        
        countCriteria.groupBy(criteria.getGroupList());
        countCriteria.distinct(criteria.isDistinct());
        
        return em.createQuery(countCriteria).getSingleResult();

}
}

在上面函数的最后一行升级到 Spring Boot 3、Hibernate 6 后，我在代码中遇到了这个问题。请推荐。TIA

Answer 1

按照这个方法就可以了

ublic Long count() {
        var countBuilder = (HibernateCriteriaBuilder) builder; //CriteriaBuilder from class level
        var countQuery = countBuilder.createQuery(Long.class);
        var subQuery = countQuery.subquery(Tuple.class);

        var sqmSubQuery = (SqmSubQuery<Tuple>) subQuery;
        var sqmOriginalQuery = (SqmSelectStatement) query; // CriteriaQuery from class level
        var sqmOriginalQuerySpec = sqmOriginalQuery.getQuerySpec();
        var sqmSubQuerySpec = sqmOriginalQuerySpec.copy(SqmCopyContext.simpleContext());

        sqmSubQuery.setQueryPart(sqmSubQuerySpec);
        Root<?> subQuerySelectRoot = subQuery.getRoots().iterator().next();
        sqmSubQuery.multiselect(subQuerySelectRoot.get("id").alias("id"));

        countQuery.multiselect(countBuilder.count(countBuilder.literal(1)));
        countQuery.from(sqmSubQuery.distinct(true).orderBy(builder.asc(subQuerySelectRoot.get("id"))));

        return entityManager.createQuery(countQuery).getSingleResult();
    }

或 研究 这篇文章https://hibernate.atlassian.net/browse/HHH-17410

UPD 我对以前的版本有奇怪的问题（有时它尝试从另一个请求表请求对象），所以现在看起来像：

public Long count(CriteriaBuilder builder, CriteriaQuery query) {
        var countBuilder = (HibernateCriteriaBuilder) builder;
        var countQuery = countBuilder.createQuery(Long.class);
        var subQuery = countQuery.subquery(Tuple.class);

        var sqmSubQuery = (SqmSubQuery<Tuple>) subQuery;
        var sqmOriginalQuery = (SqmSelectStatement) query;
        var sqmOriginalQuerySpec = sqmOriginalQuery.getQuerySpec();
        var sqmSubQuerySpec = sqmOriginalQuerySpec.copy(SqmCopyContext.simpleContext());
        sqmSubQuery.setQueryPart(sqmSubQuerySpec);
        Root<?> subQuerySelectRoot = subQuery.getRoots().iterator().next();

        sqmSubQuery.multiselect(subQuerySelectRoot.get("id").alias("id"));

        countQuery.multiselect(countBuilder.count(countBuilder.literal(1)));
        countQuery.from(sqmSubQuery.distinct(true).orderBy(builder.asc(subQuerySelectRoot.get("id"))));
        return entityManager.createQuery(countQuery).getSingleResult();
    }

Answer 2

我正在尝试实现上述内容 countQuery.from(sqmSubQuery.distinct(true).orderBy(builder.asc(subQuerySelectRoot.get(“id”)))); 我收到错误： 无法解析方法“from(org.hibernate.query.criteria.JpaSubQuery)”

知道如何解决这个问题吗？ 感谢你的帮助。谢谢！