起订量覆盖之前的设置？

Question

嗨，我正在尝试使用两个可能的输入来设置类方法的模拟。当我检查输出时，仅最后一次设置返回预期输出。第一个没有。非常感谢任何帮助。

[Test]
public void ClimbOnceTwoNeighbour_Sample()
{
    stateConverter = new Mock<StateConverter>();

    solution = new Mock<Solution>();
    state = new Mock<State>();

    var neightbourSolution1 = new Mock<Solution>();
    var neighbourState1 = new Mock<State>();
    var neightbourSolution2 = new Mock<Solution>();
    var neighbourState2 = new Mock<State>();

    stateConverter.Setup(x => x.FromSolution(neightbourSolution1.Object, It.IsAny<State>())).Returns(neighbourState1.Object);
    stateConverter.Setup(x => x.FromSolution(neightbourSolution2.Object, It.IsAny<State>())).Returns(neighbourState2.Object);

    var state1 = stateConverter.Object.FromSolution(neightbourSolution1.Object, state.Object);//return null ????
    var state2 = stateConverter.Object.FromSolution(neightbourSolution2.Object, state.Object);//return neighbourState2.Object)


    Assert.AreEqual(neighbourState2.Object, state2);//pass test here
    Assert.AreEqual(neighbourState1.Object, state1);//fail here due to null is returned from previous statement

}

Answer 1

我已复制您的代码片段并创建空类以使其编译。它按预期工作。请尝试一下并告诉我结果如何。

这是代码：

using Moq;

namespace ConsoleApplication1
{
class Program
{
    static void Main(string[] args)
    {
        var stateConverter = new Mock<StateConverter>();

        var solution = new Mock<Solution>();
        var state = new Mock<State>();

        var neightbourSolution1 = new Mock<Solution>();
        var neighbourState1 = new Mock<State>();
        var neightbourSolution2 = new Mock<Solution>();
        var neighbourState2 = new Mock<State>();

        stateConverter.Setup(x => x.FromSolution(neightbourSolution1.Object, It.IsAny<State>())).Returns(neighbourState1.Object);
        stateConverter.Setup(x => x.FromSolution(neightbourSolution2.Object, It.IsAny<State>())).Returns(neighbourState2.Object);

        var state1 = stateConverter.Object.FromSolution(neightbourSolution1.Object, state.Object);
        var state2 = stateConverter.Object.FromSolution(neightbourSolution2.Object, state.Object);
    }
}

public class State{}

public class Solution{}

public abstract class StateConverter
{
    public abstract State FromSolution(Solution p0, State isAny);
}

}

Answer 2

我使用 Moq 的习惯之一是使用完整的 It.Is(o => o == object) 语法，以避免设置不明确或隐式时出现任何问题。 Moq 可能只是简单地获取设置中的对象并覆盖其中已有的任何其他对象。

stateConverter.Setup(x => x.FromSolution(neightbourSolution1.Object, It.IsAny<State>())).Returns(neighbourState1.Object);
stateConverter.Setup(x => x.FromSolution(neightbourSolution2.Object, It.IsAny<State>())).Returns(neighbourState2.Object);

然后看起来像

stateConverter.Setup(x => x.FromSolution(It.Is<Solution>(solution => solution == neightbourSolution1.Object), It.IsAny<State>())).Returns(neighbourState1.Object);
stateConverter.Setup(x => x.FromSolution(It.Is<Solution>(solution => solution == neightbourSolution2.Object), It.IsAny<State>())).Returns(neighbourState2.Object);

我不太确定这是否能解决您的问题，因为隐含性非常清楚。 :/

Answer 3

你尝试过这样的事情吗？

[Test]
public void ClimbOnceTwoNeighbour_Sample()
{
    stateConverter = new Mock<StateConverter>();

    solution = new Mock<Solution>();
    state = new Mock<State>();

    var neightbourSolution1 = new Mock<Solution>();
    var neighbourState1 = new Mock<State>();
    var neightbourSolution2 = new Mock<Solution>();
    var neighbourState2 = new Mock<State>();

    stateConverter.Setup(x => x.FromSolution(neightbourSolution1.Object, It.IsAny<State>())).Returns(neighbourState1.Object);
    var state1 = stateConverter.Object.FromSolution(neightbourSolution1.Object, state.Object);//return null ????


    stateConverter.Setup(x => x.FromSolution(neightbourSolution2.Object, It.IsAny<State>())).Returns(neighbourState2.Object);
    var state2 = stateConverter.Object.FromSolution(neightbourSolution2.Object, state.Object);//return neighbourState2.Object)


    Assert.AreEqual(neighbourState2.Object, state2);//pass test here
    Assert.AreEqual(neighbourState1.Object, state1);//fail here due to null is returned from previous statement

}

我认为这样，当你将第一次返回的结果赋值给你的state1时，你可以再次使用Setup并将结果添加到state2;)