运行游戏时出现空白窗口

问题描述 投票:1回答:1

我正在为游戏使用pygame,但是当我启动它时,我可以看到一个黑色的窗口。当您单击关闭按钮时,您可以在短时间内看到游戏的所有对象。

import pygame

pygame.init()

win = pygame.display.set_mode((800, 600))

pygame.display.set_caption('World of Fighters')

walkRight = [pygame.image.load('g_right1.png'),
pygame.image.load('g_right2.png'), pygame.image.load('g_right3.png'),
pygame.image.load('g_right4.png')]

walkLeft = [pygame.image.load('g_left1.png'),
pygame.image.load('g_left2.png'), pygame.image.load('g_left3.png'),
pygame.image.load('g_left4.png')]

bg = pygame.image.load('bg.jpg')
playerStand = pygame.image.load('g_stand.png')


clock = pygame.time.Clock()


#player 2
x2 = 720
y2 = 500

width2 = 35
height2 = 50
speed2 = 15

left2 = False
right2 = False
animCount2 = 0

isJump2 = False
jumpCount2 = 10


#player 1
x = 50
y = 500

width = 35
height = 50
speed = 15

left = False
right = False
animCount = 0

isJump = False
jumpCount = 10

#blue
color = (0, 0, 255)

run = True

def drawWindow():
    global animCount
    win.blit(bg, (0, 0))

    if animCount + 1 >= 30:
        animCount = 0

    if left:
        win.blit(walkLeft[animCount // 5], (x, y))
        animCount += 1
    elif right:
        win.blit(walkRight[animCount // 5], (x, y))
        animCount += 1
    else:
        win.blit(playerStand, (x, y))



    pygame.display.update() 

while run:
    clock.tick(30)

    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            run = False

    keys = pygame.key.get_pressed()

    #p1
    if keys[pygame.K_a] and x > 5:
        x -= speed
        left = True
        right = False   
    elif keys[pygame.K_d] and x < 800 - width - 5:
        x += speed
        left = False
        right = True
    else:
        right = False
        left = False
        animCount = 0
    if not(isJump):
        if keys[pygame.K_SPACE]:
            isJump = True
    else:
        if jumpCount >= -10:
            if jumpCount < 0:
                y += (jumpCount ** 2) / 2
            else:
                y -= (jumpCount ** 2) / 2
            jumpCount -= 1

        else:
            isJump = False
            jumpCount = 10


    #p2
    if keys[pygame.K_LEFT] and x2 > 5:
        x2 -= speed2
        left2 = True
        right2 = False  
    elif keys[pygame.K_RIGHT] and x2 < 800 - width2 - 5:
        x2 += speed2
        left2 = False
        right2 = True
    if not(isJump2):

        if keys[pygame.K_RCTRL]:
            isJump2 = True
    else:
        right2 = False
        left2 = False
        animCount2 = 0
        if jumpCount2 >= -10:
            if jumpCount2 < 0:
                y2 += (jumpCount2 ** 2) / 2
            else:
                y2 -= (jumpCount2 ** 2) / 2
            jumpCount2 -= 1

        else:
            isJump2 = False
            jumpCount2 = 10

drawWindow()


pygame.quit()

此外,该游戏将是2位像素艺术风格的动态战斗机,但我找不到此错误的答案,因为我看了一个教程,并且拥有与视频相同的代码。

python python-3.x pygame window 2d-games
1个回答
0
投票

是问题Indentation。必须在主应用程序循环中而不是循环之后调用drawWindow()

您要做的是:

while run:
   clock.tick(30)
   # [...]

drawWindow()

pygame.quit() 

您要做的是

while run:
    clock.tick(30)
    # [...]

    drawWindow()

pygame.quit() 
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