有一列数据框
disposition
---------
NO ANSWER
ANSWERED
FAILED
BUSY
ERROR
WARNING
CANCEL
如何根据条件替换值:
WHEN disposition = 'NO ANSWER' THEN 0
WHEN disposition = 'ANSWERED' THEN 1
WHEN disposition = 'FAILED' THEN 2
WHEN disposition = 'BUSY' THEN 3
ELSE 9
希望的结果是
disposition
---------
0
1
2
3
9
9
9
代码
m = {'NO ANSWER': 0, 'ANSWERED': 1, 'FAILED': 2, 'BUSY': 3}
df['disposition'] = df['disposition'].map(m).fillna(9).astype('int')
df
disposition
0 0
1 1
2 2
3 3
4 9
5 9
6 9