如何用 2 个（或更多）Mysql select 语句填充 php 生成的 html 表

Question

php 和 MYSQL 新手，需要一些帮助，所以请温柔一点 我有一些使用 php echo 填充 HTML 表的代码。 声明是：

$query= "SELECT Distinct AgeGrp, Gender,Dist, Stroke, First, 
                Family, Name, Year, Time, Event, Date 
        FROM JLSSWIMMING1 
        WHERE Year = '7'  
        and Stroke = 'Freestyle'" ;  

我想添加更多选择语句，然后在同一个 html 表中显示结果，例如

$query2= "SELECT Distinct AgeGrp, Gender,Dist, Stroke, First, 
                Family, Name, Year, Time, Event, Date 
          FROM JLSSWIMMING1 
          WHERE Year = '7'  
          and Stroke = 'Backstroke'" ;

提前致谢

从研究来看，我可能需要一个数组（而不是连接），但我目前正在努力。 这是我当前的代码：

<?php

    try {
        $pdo = new PDO("mysql:host=$servername;dbname=$dbname;charset=utf8", $username, $password);
        $pdo->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
        $query= "SELECT Distinct AgeGrp, Gender,Dist, Stroke, First, Family, Name, Year, Time, Event, Date FROM JLSSWIMMING1 WHERE Year = '7'  and Stroke = 'Freestyle'" ;  
        $stmt = $pdo->prepare($query);     
        $stmt->execute();
        $result = $stmt->fetchAll(PDO::FETCH_ASSOC);
         if (count($result) > 0) {
        echo "<br>";
        echo '<table class="special-table">';
        echo '<thead class="fixed-header">';
        echo '<tr>
            <th>Pos.</th><th class="left-align">Name</th><th class="left-align">Stroke</th><th>Yr</th><th>Dist</th><th>Time</th><th>AgeGrp</th><th>Gen.</th><th>DAte</th><th>Event</th>
                </tr></thead><tbody>';
                
                foreach ($result as $row) {
                    echo "<tr>
                            <td >" . $cnt++ ."</td>
                            <td class='left-align'>" . $row["Name"] . "</td>
                            <td class='left-align'>" . $row["Stroke"] . "</td>
                            <td >" . $row["Year"] . "</td>
                            <td >" . $row["Dist"] . "</td>
                            <td >" . $row["Time"] . "</td>
                            <td >" . $row["AgeGrp"] . "</td>
                            <td >" . $row["Gender"] . "</td>
                            <td >" . Date('d-m-y', strtotime($row['Date'])) . "</td>
                            <td >" . $row["Event"] . "</td>
                        </tr>";
                }
                echo "</table></div>";
          }
                 else {
                echo "<br>";
                echo "<br>";
                echo "<div style='font-size: 42px;'>  No results found "     ;
            }
        } catch (PDOException $e) {
            die("Connection failed: " . $e->getMessage());
        }
        // Close the database connection
        $pdo = null;

?>

Answer 1

使用这样的一个查询即可在一次选择中获取您想要的所有数据。您应该始终尝试运用查询的力量，而不是将关系数据库视为平面文件。

$query= "SELECT Distinct AgeGrp, Gender,Dist, Stroke, First, 
                Family, Name, Year, Time, Event, Date 
        FROM JLSSWIMMING1 
        WHERE Year = '7'  
        and ( Stroke = 'Freestyle' OR Stroke = 'Backstroke')";  

或者你可以像这样使用 IN() 子句

$query= "SELECT Distinct AgeGrp, Gender,Dist, Stroke, First, 
                Family, Name, Year, Time, Event, Date 
        FROM JLSSWIMMING1 
        WHERE Year = '7'  
        and Stroke IN('Freestyle', 'Backstroke')";