我有一个文件夹中创建一个文本文件，并拉上该文件夹和测试的目的保存@same位置。我想在创建后直接下载用户机器上的zip文件。我使用dotnetzip库，也做了以下内容：
Response.Clear();
Response.ContentType = "application/zip";
Response.AddHeader("content-disposition", "filename=" + "sample.zip");
using (ZipFile zip = new ZipFile())
{
zip.AddDirectory(Server.MapPath("~/Directories/hello"));
zip.Save(Server.MapPath("~/Directories/hello/sample.zip"));
}
是否有人可以建议如何压缩文件可以在用户端下载。？
您可以使用控制器的File方法返回一个文件，如：
public ActionResult Download()
{
using (ZipFile zip = new ZipFile())
{
zip.AddDirectory(Server.MapPath("~/Directories/hello"));
zip.Save(Server.MapPath("~/Directories/hello/sample.zip"));
return File(Server.MapPath("~/Directories/hello/sample.zip"),
"application/zip", "sample.zip");
}
}
如果不需要的zip文件，否则将被存储，无需将其写入到服务器上的文件：
public ActionResult Download()
{
using (ZipFile zip = new ZipFile())
{
zip.AddDirectory(Server.MapPath("~/Directories/hello"));
MemoryStream output = new MemoryStream();
zip.Save(output);
return File(output.ToArray(), "application/zip", "sample.zip");
}
}
首先，考虑一种无需服务器的磁盘上创建任何文件。不好的做法。我建议创建一个文件，并在内存荏苒它来代替。希望，你会发现下面的有用我的榜样。
/// <summary>
/// Zip a file stream
/// </summary>
/// <param name="originalFileStream"> MemoryStream with original file </param>
/// <param name="fileName"> Name of the file in the ZIP container </param>
/// <returns> Return byte array of zipped file </returns>
private byte[] GetZippedFiles(MemoryStream originalFileStream, string fileName)
{
using (MemoryStream zipStream = new MemoryStream())
{
using (ZipArchive zip = new ZipArchive(zipStream, ZipArchiveMode.Create, true))
{
var zipEntry = zip.CreateEntry(fileName);
using (var writer = new StreamWriter(zipEntry.Open()))
{
originalFileStream.WriteTo(writer.BaseStream);
}
return zipStream.ToArray();
}
}
}
/// <summary>
/// Download zipped file
/// </summary>
[HttpGet]
public FileContentResult Download()
{
var zippedFile = GetZippedFiles(/* your stream of original file */, "hello");
return File(zippedFile, // We could use just Stream, but the compiler gets a warning: "ObjectDisposedException: Cannot access a closed Stream" then.
"application/zip",
"sample.zip");
}
注意到上面的代码：
MemoryStream实例需要检查它是否是开放的，有效的，等我忽略他们。我宁愿传递的文件内容，而不是一个MemoryStream实例，使代码更健壮的字节数组，但它会是太多了这个例子。只是修复到克劳斯的解决方案：（我不能添加评论我要补充另外一个答案！）
该解决方案是伟大的，但对我来说，给了损坏的zip文件，然后我意识到，这是因为回报正在完成压缩的对象，因此没有关闭拉链，导致损坏的ZIP之前。
所以要解决，我们只是需要移动回线使用拉链块，它的工作原理之后。最后的结果是：
/// <summary>
/// Zip a file stream
/// </summary>
/// <param name="originalFileStream"> MemoryStream with original file </param>
/// <param name="fileName"> Name of the file in the ZIP container </param>
/// <returns> Return byte array of zipped file </returns>
private byte[] GetZippedFiles(MemoryStream originalFileStream, string fileName)
{
using (MemoryStream zipStream = new MemoryStream())
{
using (ZipArchive zip = new ZipArchive(zipStream, ZipArchiveMode.Create, true))
{
var zipEntry = zip.CreateEntry(fileName);
using (var writer = new StreamWriter(zipEntry.Open()))
{
originalFileStream.WriteTo(writer.BaseStream);
}
}
return zipStream.ToArray();
}
}
/// <summary>
/// Download zipped file
/// </summary>
[HttpGet]
public FileContentResult Download()
{
var zippedFile = GetZippedFiles(/* your stream of original file */, "hello");
return File(zippedFile, // We could use just Stream, but the compiler gets a warning: "ObjectDisposedException: Cannot access a closed Stream" then.
"application/zip",
"sample.zip");
}
对于那些只是想从App_Data文件夹返回现有的压缩文件（只转储在您的zip文件存在），在家庭控制器创建这个操作方法：
public FileResult DownLoad(string filename)
{
var content = XFile.GetFile(filename);
return File(content, System.Net.Mime.MediaTypeNames.Application.Zip, filename);
}
获取文件是一个扩展方法：
public static byte[] GetFile(string name)
{
string path = AppDomain.CurrentDomain.GetData("DataDirectory").ToString();
string filenanme = path + "/" + name;
byte[] bytes = File.ReadAllBytes(filenanme);
return bytes;
}
首页控制器索引视图看起来是这样的：
@model List<FileInfo>
<table class="table">
<tr>
<th>
@Html.DisplayName("File Name")
</th>
<th>
@Html.DisplayName("Last Write Time")
</th>
<th>
@Html.DisplayName("Length (mb)")
</th>
<th></th>
</tr>
@foreach (var item in Model)
{
<tr>
<td>
@Html.ActionLink("DownLoad","DownLoad",new {filename=item.Name})
</td>
<td>
@Html.DisplayFor(modelItem => item.Name)
</td>
<td>
@Html.DisplayFor(modelItem => item.LastWriteTime)
</td>
<td>
@Html.DisplayFor(modelItem => item.Length)
</td>
</tr>
}
</table>
主索引文件的操作方法：
public ActionResult Index()
{
var names = XFile.GetFileInformation();
return View(names);
}
凡GetFileInformation是一个扩展的方法：
public static List<FileInfo> GetFileInformation()
{
string path = AppDomain.CurrentDomain.GetData("DataDirectory").ToString();
var dirInfo = new DirectoryInfo(path);
return dirInfo.EnumerateFiles().ToList();
}
创建一个返回GET，像这样的只FileResult控制器动作：
[HttpGet]
public FileResult Download()
{
// Create file on disk
using (ZipFile zip = new ZipFile())
{
zip.AddDirectory(Server.MapPath("~/Directories/hello"));
//zip.Save(Response.OutputStream);
zip.Save(Server.MapPath("~/Directories/hello/sample.zip"));
}
// Read bytes from disk
byte[] fileBytes = System.IO.File.ReadAllBytes(
Server.MapPath("~/Directories/hello/sample.zip"));
string fileName = "sample.zip";
// Return bytes as stream for download
return File(fileBytes, "application/zip", fileName);
}