如何在不使用 setTimeout [重复]的情况下使此代码异步运行

Question

const delayFunction = async () => {
  const startTime = new Date().getTime();

  const duration = 10000; 

  console.log('START')
  while (new Date().getTime() - startTime < duration) {
   // this loop runs for 10 seconds
  }
  console.log('STOP');
};

const starterFunction = async () => {
  console.log('1');
  delayFunction();
  console.log('2');
  return 'DONE'
};

console.log(starterFunction())

所以现在我想要如下输出：

1

2

完成

开始

停止

如果有人知道如何通过异步编程实现这一点，请帮助我。

我尝试创建一个新的承诺并尝试执行其中的代码，但即使这样似乎也不起作用。

const delayFunction = async () => {
  return new Promise((resolve,reject) => {
     const startTime = new Date().getTime();

     const duration = 10000; 

     console.log('START')
     while (new Date().getTime() - startTime < duration) {
     // this loop runs for 10 seconds
     }
     resolve(console.log('STOP'));
  });
};

Answer 1

  const duration = 10000;

  console.log('START');

  return new Promise((resolve) => {
    setTimeout(() => {
      console.log('STOP');
      resolve();
    }, duration);
  });
};

const starterFunction = async () => {
  console.log('1');
  console.log('2');
  await delayFunction();
  return 'DONE';
};

(async () => {
  await starterFunction();
})();