如何在dart上发出HTTP请求并传递参数

问题描述 投票:1回答:1

http请求的dart代码并向请求添加参数。

像这样的东西,但在飞镖

params = {'key': '54321'}
resp = requests.get('https://api.example.com/test', data = params)
dart httprequest url-parameters
1个回答
1
投票

其中一个应该做你想要的:

resp = requests.get(Uri.https('api.example.com', 'test', params).toString());

要么

resp = requests.get(Uri.parse('https://api.example.com/test').replace(queryParameters: params).toString());
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