Swift 5：向GestureRecognizer发送函数时更改标签错误

Question

我想将诸如参数之类的函数发送到gesturerecognizer，然后添加到UIlabel。所以我做了一个这样的功能：

final class ActionTag: NSObject {
    var tag = 0
    private let _action: (Int) -> ()

    init(action: @escaping (Int) -> ()) {
        _action = action
        super.init()
    }

    @objc func action() {
        _action(tag)
    }
}

在我的职能中，我有一些代码：

for index in 0..<5 {
      let dateLabel = UILabel()
      dateLabel.tag = index + 1
      addDoublePress(label: dateLabel, doubleTap: planDateDidDoubleTapped)

}

在此处定义：

private func addDoublePress(label: UILabel, doubleTap: ActionTag) {
        label.isUserInteractionEnabled = true
        doubleTap.tag = label.tag

        let doubleTapRecognizer = UITapGestureRecognizer(target: doubleTap, action: #selector(doubleTap.action))
        doubleTapRecognizer.numberOfTapsRequired = 2
        label.addGestureRecognizer(doubleTapRecognizer)
    }

    private let planDateDidDoubleTapped = ActionTag { tag in
        print("planDateDidDoubleTapped need implemention = \(tag)")
    }

但是运行时，我得到的是：planDateDidDoubleTapped需要实现= 5为什么标签只保留一个值（5）？

Answer 1

我已经解决了这个问题。我像这样更改ActionTag类：

final class ActionTag: NSObject {
        private let _action: (UITapGestureRecognizer) -> ()

        init(action: @escaping (UITapGestureRecognizer) -> ()) {
            _action = action
            super.init()
        }

        @objc func action(sender: UITapGestureRecognizer) {
            _action(sender)
        }
    }

我得到这样的标签：

private let planDateDidDoubleTapped = ActionTag { sender in
        guard let tag = (sender.view as? UILabel)?.tag else { return }
        print("planDateDidDoubleTapped need implemention = \(tag)")

    }

我发布我的答案，请大家注意。谢谢