升级到gulp 4后，gulp监视的问题

Question

链接到此问题= Gulp error: The following tasks did not complete: Did you forget to signal async completion?

[当我尝试使用以下代码运行“监视”时，出现错误：

gulp.task('watch', async function() {
    var watchJs = gulp.watch(paths.js, ['scripts']),
        watchJson = gulp.watch(paths.json, ['json']),
        watchHtml = gulp.watch(paths.html, ['html']),
        watchCss = gulp.watch(paths.css, ['css']),
        watchFonts = gulp.watch(paths.fonts, ['fonts']),
        watchAssets = gulp.watch(paths.assets, ['assets']),

        onChanged = function(event) {
            console.log('File ' + event.path + ' was ' + event.type + '. Running tasks...');
        }

    watchJs.on('change', onChanged);
    watchJson.on('change', onChanged);
    watchHtml.on('change', onChanged);
    watchCss.on('change', onChanged);
    watchFonts.on('change', onChanged);
    watchAssets.on('change', onChanged);
});

错误说：Error: watching src/js/**/*.js: watch task has to be a function (optionally generated by using gulp.parallel or gulp.series)

但是我不知道该如何处理。我尝试将异步放在gulp.task（'watch'，async function（）{上，但不起作用

Answer 1

更改

 var watchJs = gulp.watch(paths.js, ['scripts']),  // gulp v3 syntax

to

 var watchJs = gulp.watch(paths.js, gulp.serie('scripts')),  //  gulp v4 syntax

和您的其他人一样。查找从gulp v3到v4的迁移指南。