获取鼠标移动速度

问题描述 投票:0回答:2

我没有从 stackoverflow 得到准确的解决方案/计算,所以我创建了一个问题

var timestamp = null;
var mY = 0;
$(document).mousemove(function(e) {
    var now = Date.now();
    currentmY = e.pageY;



    mY = e.pageY;
    timestamp = now;
});

我需要获取鼠标移动垂直角度时的速度值。

https://jsfiddle.net/58tjr9o1/

javascript jquery html performance mousemove
2个回答
7
投票

速度就是距离除以所花费的时间:

speed = distance / time

距离是

currentmY - mY
,时间是
now - timestamp
。所以最后你得到:

var timestamp = 0;
var mY = 0;
$(document).mousemove(function(e) {
    var now = Date.now();
    var currentmY = e.screenY;

    var dt = now - timestamp;
    var distance = Math.abs(currentmY - mY);
    var speed = Math.round(distance / dt * 1000);
    console.log(dt, distance, speed);
    document.getElementById("speed").innerHTML = speed;
    
    mY = currentmY;
    timestamp = now;
});

注意

* 1000
,因为时间戳以毫秒为单位。速度单位为像素/秒

参见这个更新的小提琴


1
投票

以下代码将在 id = "update-speed" 的范围内不断更新鼠标的垂直移动速度。代码不言自明且易于理解,它只是保存了当前位置、上一个位置、当前时间和上一个时间,然后使用这个公式计算速度(速度 = (pos2 - pos1) / (time2 - time1)。

HTML

<span id="update-speed">Update speed</span>

JS

var prev_time = new Date();
var prev_pos_y = 0;

$(document).mousemove(function(e) {

var now = new Date();
current_pos_y = e.pageY;

time_interval = now.getTime() - prev_time.getTime();

if(time_interval != 0)
    {
        speed = ( Math.abs(current_pos_y - prev_pos_y) / time_interval );
}
else
    speed = 0;

console.log(speed);

$('#update-speed').text(speed);


prev_time = now;
prev_pos_y = current_pos_y;


});
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