在Grok过滤器中删除数字字符

问题描述 投票:0回答:1

我正在尝试编写Grok过滤器以解析logstash中的WSO2日志。我能够映射所有必需的属性。但是在一个属性中,我们需要删除10个数字字符。

有人可以让我知道如何以Grok模式进行操作。

示例-进入下面:

"context": [
    [
      "/app/custManagement/v2/customer/lookup/9999999999"
    ]

期望:

"context": [
    [
      "/app/custManagement/v2/customer/lookup/"
    ]

WSO2日志:

TID: [-1234] [] [2020-05-11 15:20:16,803]  INFO {org.apache.synapse.mediators.builtin.LogMediator} -  WSO2Status = SUCCESS, APIE2ETime = /app/custManagement/v2/customer/lookup/9999999999, X-External-CorrelationId = 7613691301, IN = 2020-05-11T15:20:15.656+05:30, OUT = 2020-05-11T15:20:16.803+05:30, HTTP_SC = 200, Channel = WEB, Http_Method = GET, RemoteAddress = 17.98.27.231 {org.apache.synapse.mediators.builtin.LogMediator}

Grok模式:

TID:%{SPACE}\[%{INT:tenant_id}\]%{SPACE}\[]%{SPACE}\[%{TIMESTAMP_ISO8601:hit_timestamp}\]%{SPACE}%{LOGLEVEL:level}%{SPACE}{%{JAVACLASS:java_class}}%{SPACE}-%{SPACE}WSO2Status%{SPACE}=%{SPACE}%{WORD:Status},%{SPACE}APIE2ETime%{SPACE}=%{SPACE}%{GREEDYDATA:context},%{SPACE}X-External-CorrelationId%{SPACE}=%{SPACE}%{WORD:CorrelationId},%{SPACE}IN%{SPACE}=%{SPACE}%{TIMESTAMP_ISO8601:in_timestamp},%{SPACE}OUT%{SPACE}=%{SPACE}%{TIMESTAMP_ISO8601:out_timestamp},%{SPACE}HTTP_SC%{SPACE}=%{SPACE}%{INT:http_sc},%{SPACE}Channel%{SPACE}=%{SPACE}%{WORD:channel},%{SPACE}Http_Method%{SPACE}=%{SPACE}%{WORD:http_method},%{SPACE}RemoteAddress%{SPACE}=%{SPACE}%{IP:remoteaddress}%{SPACE}{%{JAVACLASS:java_class2}}
wso2 logstash logstash-grok elk
1个回答
0
投票

替换为:

=%{SPACE}%{GREEDYDATA:context},%{SPACE}

作者

=%{SPACE}%{GREEDYDATA:context}/%{NUMBER},%{SPACE}
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