允许手机在屏幕关闭时振动

Question

我正在寻找一种方法，让我的程序在屏幕因超时关闭后使手机振动。我做了很多研究，但没有找到有效的方法。我研究了 PowerManager 类，更具体地说是 WakeLock 机制。从许多帖子的声音来看，我需要使用 WakeLock 类的 PARTIAL_WAKE_LOCK 变量。

PARTIAL_WAKE_LOCK - 确保 CPU 正在运行的唤醒锁。

但是，当屏幕关闭时，我无法让它振动手机。我知道我正确使用了 WakeLock，因为我可以让 SCREEN_DIM_WAKE_LOCK 正常工作。 PARTIAL_WAKE_LOCK 是我正在寻找的吗？

Answer 1

 @Override

    public void onCreate() {

        super.onCreate();

        // REGISTER RECEIVER THAT HANDLES SCREEN ON AND SCREEN OFF LOGIC

        IntentFilter filter = new IntentFilter(Intent.ACTION_SCREEN_ON);

        filter.addAction(Intent.ACTION_SCREEN_OFF);

        BroadcastReceiver mReceiver = new ScreenReceiver();

        registerReceiver(mReceiver, filter);

    }



    @Override

    public void onStart(Intent intent, int startId) {

        boolean screenOn = intent.getBooleanExtra("screen_state", false);

        if (!screenOn) {

            // Get instance of Vibrator from current Context
            Vibrator v = (Vibrator) getSystemService(Context.VIBRATOR_SERVICE);
           // This example will cause the phone to vibrate "SOS" in Morse Code
           // In Morse Code, "s" = "dot-dot-dot", "o" = "dash-dash-dash"
           // There are pauses to separate dots/dashes, letters, and words
           // The following numbers represent millisecond lengths
            int dot = 200;      // Length of a Morse Code "dot" in milliseconds
           int dash = 500;     // Length of a Morse Code "dash" in milliseconds
            int short_gap = 200;    // Length of Gap Between dots/dashes
           int medium_gap = 500;   // Length of Gap Between Letters
           int long_gap = 1000;    // Length of Gap Between Words
            long[] pattern = {
             0,  // Start immediately
             dot, short_gap, dot, short_gap, dot,    // s
             medium_gap,
             dash, short_gap, dash, short_gap, dash, // o
            medium_gap,
            dot, short_gap, dot, short_gap, dot,    // s
           long_gap
           };

           // Only perform this pattern one time (-1 means "do not repeat")
          v.vibrate(pattern, -1);


        } else {

            // YOUR CODE

        }

    }

注意，您必须将使用权限行添加到块之外的 Manifest.xml 文件中。

<manifest xmlns:android="http://schemas.android.com/apk/res/android" package="...">
<uses-permission android:name="android.permission.VIBRATE"/>

注意：您还必须在真机上测试此代码，模拟器无法振动

Answer 2

对我来说，解决方案是直接使用无模式振动，这样我就不必使用 PowerManager 来唤醒锁定。

Answer 3

long vibrationDuration = 10000L; // 10 second or 10000 milliseconds
int vibrationAmplitude = 200;   // between 1 and 255
Vibrator vibrator = (Vibrator) getSystemService(VIBRATOR_SERVICE);
VibrationEffect vibe = VibrationEffect.createOneShot(vibrationDuration, vibrationAmplitude);

// for API level 33 or higher
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.TIRAMISU)
    vibrator.vibrate(vibe, VibrationAttributes.createForUsage(VibrationAttributes.USAGE_MEDIA));
else
    vibrator.vibrate(vibe, new AudioAttributes.Builder().setUsage(AudioAttributes.USAGE_MEDIA).build());