无法从内部可观察数据中检索数据

问题描述 投票:-2回答:2

我遇到了这个代码的问题。我正在尝试从第二个端点收集与第一个get中返回集合中的id相关的额外详细信息。有人可以帮助如何获取实际数据,因为它返回一组可观察量。谢谢

this.http.get(`${this.apiUrl}/cinemas/location/cardiff`).pipe(
  map((data: any) => data.cinemas),
  map((cinemalist) => {
    return cinemalist.map(value => <Observable<any>>this.http.get(`https://api.cinelist.co.uk/get/cinema/${value.id}`));
  })
).subscribe(results => {
  console.log(results);
});
angular rxjs ionic4
2个回答
4
投票

而不是map,你可以用switchMapforkJoin

this.http.get(`${this.apiUrl}/cinemas/location/cardiff`).pipe(
  map((data: any) => data.cinemas),
  switchMap((cinemas) => forkJoin(cinemas.map(value => <Observable<any>>this.http.get(`https://api.cinelist.co.uk/get/cinema/${value.id}`));
  }))
).subscribe(results => {
  console.log(results);
});

如果你想保留价值,你可以尝试这样的事情:

this.http.get(`${this.apiUrl}/cinemas/location/cardiff`).pipe(
  map((data: any) => data.cinemas),
  switchMap((cinemas) => forkJoin(cinemas.map(value => <Observable<any>>this.http.get(`https://api.cinelist.co.uk/get/cinema/${value.id}`))
    .pipe(map(cinema => {...cinema,value}))
  }))
).subscribe(results => {
  console.log(results);
});

0
投票
this.http.get(`https://api.cinelist.co.uk/search/cinemas/location/${town}`).pipe(
      map((data: any) => data.cinemas),
      flatMap((cinemas) =>
        forkJoin(
          cinemas.map(value => {
            return this.http.get(`https://api.cinelist.co.uk/get/cinema/${value.id}`).pipe(
              map((result: any) => {
                return { ...result, ...value };
              }));
          })
        )
      )
    ).subscribe(x => {
      console.log(x);
    });
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