Pandas：替换字符串列值（等于，包含，区分大小写）

Question

我有如下数据仓库。

ID   COUNTRY   GENDER    AGE  V1   V2   V3   V4   V5
1    1    1    53   APPLE     apple     bosck     APPLE123  xApple111t
2    2    2    51   BEKO beko SIMSUNG   SamsungO123    ttBeko111t
3    3    1    24   SAMSUNG   bosch     SEMSUNG   BOSC1123  uuSAMSUNG111t

如果列表中有相同值或包含特定值，我想替换为np.nan。我在下面尝试过，但是发生了错误。

remove_list = ['APPLE', 'BEKO']

remove_contain_list = ['SUNG', 'bosc']

df.iloc[:,4:].str.replace(remove_list, np.nan, case=False) # exact match & case sensitive
df.iloc[:,4:].str.contains(remove_contain_list, np.nan, case=False) # contain & case sensitive

我该如何解决这些问题？

Answer 1

用途：

remove_list = ['APPLE', 'BEKO']
remove_contain_list = ['SUNG', 'bosc']

s = df.iloc[:,4:].stack()
m1 = s.str.lower().isin([x.lower() for x in remove_list])
m2 = s.str.contains('|'.join(remove_contain_list), case=False)
s = s.mask(m1 | m2)

df.iloc[:,4:] = s.unstack()
print (df)
   ID  COUNTRY  GENDER  AGE   V1   V2   V3        V4          V5
0   1        1       1   53  NaN  NaN  NaN  APPLE123  xApple111t
1   2        2       2   51  NaN  NaN  NaN       NaN  ttBeko111t
2   3        3       1   24  NaN  NaN  NaN       NaN         NaN