旋转一张图

Question

我想画第一个旋转的图形，而第二个旋转的图形。当我运行下面的代码时，它没有显示第一个数字，但旋转了第二个数字。重置无效。我需要保持数字顺序不变。

    Private Sub Form17_Paint(ByVal sender As Object, ByVal e As System.Windows.Forms.PaintEventArgs) Handles Me.Paint
        Dim x, y As Integer
        e.Graphics.SmoothingMode = SmoothingMode.HighQuality
        'Figure 1
        Dim Mx As Matrix = New Matrix()
        x = 59 : y = 25
        Mx.RotateAt(90, New Point(x, y), MatrixOrder.Append)
        e.Graphics.Transform = Mx
        e.Graphics.DrawEllipse(New Pen(Color.Green, 1), New Rectangle(x + 3, y - 5, 10, 10))
        e.Graphics.DrawLine(New Pen(Color.Green, 1), x, y - 2, x + 13, y - 2)
        e.Graphics.DrawLine(New Pen(Color.Green, 1), x, y + 2, x + 13, y + 2)
        e.Graphics.DrawLine(New Pen(Color.Green, 1), x + 8, y - 5, x + 8, y + 5)
        Mx.Reset()
        'Figura 2
        e.Graphics.DrawEllipse(New Pen(Color.Blue, 1), New Rectangle(x + 3, y - 5, 10, 10))
        e.Graphics.DrawLine(New Pen(Color.Blue, 1), x, y - 2, x + 13, y - 2)
        e.Graphics.DrawLine(New Pen(Color.Blue, 1), x, y + 2, x + 13, y + 2)
        e.Graphics.DrawLine(New Pen(Color.Blue, 1), x + 8, y - 5, x + 8, y + 5)
    End Sub

怎么了？

Answer 1

这两个数字相互重叠。重置后重新分配矩阵：

Mx.Reset()
e.Graphics.Transform = Mx ' <========