根据带有调查软件包的条件遍历列和打印比例或均值表

问题描述 投票:0回答:1

我尝试遍历各列,如果满足条件,则打印比例表,如果不满足条件,则打印均值表。

数据

library(survey)
dat <- data.frame(id=c(1,2,3), weight=c(0,2,0.1), var1=c(2,3,4), var2=c(2,6,7))
design <- svydesign(id=~1, weights=~weight, data=dat)
cols <- c("var1", "var2")
type <- c("prop", "mean")

我尝试过:

for(i in seq_along(cols)){ 
ifelse(type[i]=="prop", 
print(prop.table(svytable(bquote(~.(as.name(cols[i]))), design))), 
            print(svymean(bquote(~.(as.name(cols[i]))), design))) }

我收到此错误消息:

Error in array(x, c(length(x), 1L), if (!is.null(names(x))) list(names(x),  : 
'data' must be of a vector type, was 'language'
r survey
1个回答
0
投票

我不太确定为什么bquote会给您这么多问题,但是如果我使用公式,它可以正常工作:

for(i in seq_along(cols)){
FORMULA= as.formula(paste("~",cols[i]))
ifelse(type[i]=="prop", 
print(prop.table(svytable(FORMULA, design))), 
            print(svymean(FORMULA, design))) }

var1
         2          3          4 
0.00000000 0.95238095 0.04761905 
       mean     SE
var2 6.0476 0.0786
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