MongoDB 按多个字段聚合排序

Question

这是我的数据：

{
   "name": "some name",
   "blockNumber": 10,
   "uniqueId: 2
},
{
   "name": "some name",
   "blockNumber": 9,
   "uniqueId: 3
},
{
   "name": "some name",
   "blockNumber": 10,
   "uniqueId: 1
},

这是我的询问：

myModel.aggregate([
        {
          $match: someFilter,
        },
        {
          $sort: { blockNumber: -1 },
        },
])

就有了预期的结果：

{
   "name": "some name",
   "blockNumber": 10,
   "uniqueId: 1
},
{
   "name": "some name",
   "blockNumber": 10,
   "uniqueId: 2
},
{
   "name": "some name",
   "blockNumber": 9,
   "uniqueId: 3
}

我正在寻找一种方法，仅当多个文档的 blockNum 相同时，才根据第二个值（在本例中为 uniqueId）对数据进行额外排序，以便最终结果也按降序 uniqueId 排序。示例：

{
   "name": "some name",
   "blockNumber": 10,
   "uniqueId: 2
},
{
   "name": "some name",
   "blockNumber": 10,
   "uniqueId: 1
},
{
   "name": "some name",
   "blockNumber": 9,
   "uniqueId: 3
}
    

Answer 1

我实际上想通了：只需在排序阶段添加第二个字段即可。 查询是：

myModel.aggregate([
        {
          $match: someFilter,
        },
        {
          $sort: { blockNumber: -1, uniqueId: -1 },
        },
])

结果：

{
   "name": "some name",
   "blockNumber": 10,
   "uniqueId: 2
},
{
   "name": "some name",
   "blockNumber": 10,
   "uniqueId: 1
},
{
   "name": "some name",
   "blockNumber": 9,
   "uniqueId: 3
}

Answer 2

.sort({ $natural: 1 })

我实际上想通了：只需在排序阶段添加第二个字段即可。查询是：