我读了this answer,但我相信有更好的方法在Guzzle中创建一个http url查询,我正在寻找这样的东西,但是无法让它正常工作,我也不知道是否有办法转储url字符串看它是否正确处理。有人能告诉我这样做的正确方法吗?
// works correctly
$client = New GuzzleHttp\Client();
$request = $client->get('http://192.168.50.8/foo?-db=database&-lay=layout&-find');
print_r($request->getBody());
不行
$request = $client->get($config->Layout['server'], [], [
'query' => [
$config->Layout['switches'], // ([ '-db' => 'database', '-lay' => 'layout', '-find' => true)
$config->Layout['options'], // other params
]
]);
我也有同样的问题。我找到了解决方案
public static function getGroupList($current=false) {
$response = self::getRestClient()->get(
[
'domains/{domainId}/pricelists',
['domainId' => self::getDomainId()]
],
[
'query' => [
current => $current
]
]
);
return new RestResponse($response);
尝试
$response = $client->get(
[
$config->Layout['server'],
[]
],
[
'query' => [
$config->Layout['switches'], // ([ '-db' => 'database', '-lay' => 'layout', '-find' => true)
$config->Layout['options'], // other params
]
]
);
正确答案的另一种变化:
$params = [
'query' => [
'option_1' => string,
'option_2' => string
]
];
然后打电话给你的请求:
$response = $guzzle_client->request('GET','/api.com',$params);