如何使用|| and && 在 and if 语句中？ [重复]

Question

我试图让 if 语句来检测这两个数组是否有相等的部分。

const winningCombos = [
  [1, 2, 3],
  [4, 5, 6],
  [7, 8, 9]
]
const mySpots = [
  [1, 2, 3],
  [4, 5, 6],
  [7, 8, 9]
]

function test() {
  winningCombos[0].splice(0, 3, 'testsss')
  //position 0 remove 1
  if (winningCombos[0] || winningCombos[1] || winningCombos[2] === mySpots[0] || mySpots[1] || mySpots[2]) {
    document.getElementById("test").innerHTML = 'sucess'
  } else {
    document.getElementById("test").innerHTML = 'fail'
  }
}

但我也试图让 if 语句变得像

if ((winningCombos[0] OR winningCombos[1] OR winningCombos[2]) is equal to(mySpots[0] || mySpots[1] || mySpots[2]) {
    console.log('success');
  };

大家能找到什么解决办法吗？

Answer 1

您必须迭代数组并比较项目

function findSimilarItems(a, b) {
  let similarities = [];
  if (a.length !== b.length) {
    throw new Error("Arrays or their rows are not of the same length.");
  }
  for (let i = 0; i < a.length; i++) {
    let rowSimilarities = [];

    for (let j = 0; j < a[i].length; j++) {
      if (a[i][j] === b[i][j]) {
        rowSimilarities.push(a[i][j]);
      }
    }

    similarities.push(rowSimilarities);
  }

  return similarities;
}


const a = [
  [1, 2, 3],
  [4, 5, 6],
  [7, 8, 9],
  [1, 2, 3],
  [5, 9, 0]
];
const b = [
  [1, 2, 3],
  [4, 5, 6],
  [7, 8, 9],
  [1, 2],
  [1, 2]
];

console.log(findSimilarItems(a, b));