在 Pandas 数据框列中创建迷你图条形图

问题描述 投票:0回答:1

我希望在 Jupyter 笔记本中的 pandas 数据框中复制下面的图像。 2020年订单标题不需要。我发现了这个页面https://github.com/crdietrich/sparklines/blob/master/Pandas%20Sparklines%20Demo.ipynb,它似乎在数据框中添加了迷你图,但不是条形图。任何见解将不胜感激!下面的代码在数据框列中提供了迷你图,但如图所示,我希望使用以下示例数据堆叠条形图。

# example data
data = [[20, 10], [50, 15], [6, 14]]
 
# Create the pandas DataFrame
df = pd.DataFrame(data, columns=['Orchid', 'Rose'])
 
# print dataframe.
print(df)

我正在寻找的输出应该类似于下图。

在列中显示迷你图,但不显示堆叠条形的示例代码。

import numpy as np
import pandas as pd
from scipy import stats
import matplotlib.pyplot as plt
%matplotlib inline

import sparklines

# Create some data

density_func = 78
mean, var, skew, kurt = stats.chi.stats(density_func, moments='mvsk')
x_chi = np.linspace(stats.chi.ppf(0.01, density_func),
                    stats.chi.ppf(0.99, density_func), 100)
y_chi = stats.chi.pdf(x_chi, density_func)

x_expon = np.linspace(stats.expon.ppf(0.01), stats.expon.ppf(0.99), 100)
y_expon = stats.expon.pdf(x_expon)

a_gamma = 1.99
x_gamma = np.linspace(stats.gamma.ppf(0.01, a_gamma),
                      stats.gamma.ppf(0.99, a_gamma), 100)
y_gamma = stats.gamma.pdf(x_gamma, a_gamma)

n = 100

np.random.seed(0)  # keep generated data the same for git commit

data = [np.random.rand(n), 
        np.random.randn(n), 
        np.random.beta(2, 1, size=n), 
        np.random.binomial(3.4, 0.22, size=n), 
        np.random.exponential(size=n),
        np.random.geometric(0.5, size=n), 
        np.random.laplace(size=n), 
        y_chi, 
        y_expon, 
        y_gamma]

function = ['rand',
            'randn',
            'beta',
            'binomial',
            'exponential',
            'geometric',
            'laplace',
            'chi',
            'expon',
            'gamma']

df = pd.DataFrame(data)
df['function'] = function

df

# Define range of data to make sparklines

a = df.ix[:, 0:100]

# Output to new DataFrame of Sparklines

df_out = pd.DataFrame()
df_out['sparkline'] = sparklines.create(data=a)
sparklines.show(df_out[['sparkline']])

# Insert Sparklines into source DataFrame

df['sparkline'] = sparklines.create(data=a)
sparklines.show(df[['function', 'sparkline']])

# Detailed Formatting

df_out = pd.DataFrame()
df_out['sparkline'] = sparklines.create(data=a,
                                        color='#1b470a',
                                        fill_color='#99a894',
                                        fill_alpha=0.2,
                                        point_color='blue',
                                        point_fill='none',
                                        point_marker='*',
                                        point_size=3,
                                        figsize=(6, 0.25))
sparklines.show(df_out[['sparkline']])

# Example Data and Sparklines Layout

df_copy = df[['function', 'sparkline']].copy()

df_copy['value'] = df.ix[:, 100]

df_copy['change'] = df.ix[:,98] - df.ix[:,99]

df_copy['change_%'] = df_copy.change / df.ix[:,99]

sparklines.show(df_copy)
python pandas matplotlib plotly sparklines
1个回答
0
投票

您可以使用 Styler 进行调整,使用 hacky

bar
:

st = (
    df.assign(
        bar=df["Orchid"].fillna(df["Rose"]),
        tmp=df["Orchid"] + df["Rose"],
    )
    .style.set_caption("Orders in 2020")
    .bar(subset=["bar", "tmp"], color="#fb9c04", axis=1)
    .set_table_styles(
        [
            {
                "selector": "td.col2",
                "props": "background-color: #668ed2"
            },
            {
                "selector": "caption",
                "props": "font-size: large; font-weight: bold",
            },
        ],
    )
    .hide(subset="tmp", axis=1)
    .format("", na_rep="", subset="bar")
    .format("${:,.2f}", na_rep="No Data", subset=["Orchid", "Rose"])
    .format_index(lambda c: c if c != "col" else "", axis=1)
    .map_index(lambda i: "font-weight: bold")
    .format_index(lambda i: i + 1)
)

输出:

使用的输入(

df
):

df = pd.DataFrame(
    {
        "Orchid": [
            3500.0, 4800.0, 1400.0, None, 7800.0, 6800.0,
            8500.0, 6200.0, 9000.0, 7300.0, 8300.0, 11300.0,
        ],
        "Rose": [
            3200.0, 2500.0, 3700.0, 5600.0, 8000.0, 3800.0,
            None, 7720.0, 8380.0, 9100.0, 9700.0, 10360.0,
        ],
    }
)
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