日期分割和删除时区

Question

我有包含以下日期的数组

{
 Mon Feb 17 2020 00:00:00 GMT+0530 (India Standard Time)
,Tue Feb 18 2020 00:00:00 GMT+0530 (India Standard Time)
,Wed Feb 19 2020 00:00:00 GMT+0530 (India Standard Time)
,Thu Feb 20 2020 00:00:00 GMT+0530 (India Standard Time)
}

如何删除时区并将此日期转换为（“日期/月/年”），我需要使用（/）并将它们返回到明智的网格列。这样的例子

 -               |[17/02/2020]   |   [18/02/2020]  |  [19/02/2020]
 1 -----         |     -         |    -            |  -
 2 -----         |     -         |    -            |  -

Answer 1

您可以删除时区部分，将该字符串转换为日期，然后返回适当格式的字符串：

const dates = [
        'Mon Feb 17 2020 00:00:00 GMT+0530 (India Standard Time)',
        'Tue Feb 18 2020 00:00:00 GMT+0530 (India Standard Time)',
        'Wed Feb 19 2020 00:00:00 GMT+0530 (India Standard Time)',
        'Thu Feb 20 2020 00:00:00 GMT+0530 (India Standard Time)',
      ],
      result = dates.map(date => new Date(date.replace(/ GMT.*/,'')).toLocaleDateString('en-GB'))
      
console.log(result)