我有一个名为A的数据框,在单独的列中有经度和纬度。样本数据
ID Lat Long
a 10.773046 76.6392061
b 10.7751978 76.6368363
c 12.954027 78.988818
d 12.9608638 77.521573
我有一个名为Test的数据框,在单独的列中有lat long。样本数据
Store Lat Long
a 21.244769 81.63861
b 9.919337 78.14844
c 10.053961 76.32757
d 13.829922 77.49369
e 23.849729 77.93647
我想循环遍历每个ID,以找到距他的经纬度和商店经纬度最近的商店的最小距离。因此ID a将检查a,b,c,d和e并找到最近的商店。
目标-查找最小距离和商店名称。
输出应显示我
Id Lat Long Store Distance
a 10.773046 76.6392061 b 50ms
a$Distance <- NA # Make an "empty" variable in my data.frame
myFunction <- function(x, y){
distm(c(lon1, lat1), c(lon2, lat2), fun = distHaversine)
}
for(ii in a){
for(jj in Test){
tempX <- a[a$Lat == ii & Store$Lat== jj, c("Lat")]
tempY <- a[a$Long == ii & Store$Long == jj, c("Long")]
# "Save" results into appropriate location in my data.frame
myFunction(tempX,tempY)
}
}
我无法获得确切的输出。
您可以检查出这个
a <- data.frame(ID = c("a", "b", "c", "d"), Lat = c(10.773046, 10.7751978, 12.954027, 12.9608638),
Long = c(76.6392061, 76.6392061, 78.988818, 77.521573))
b <- data.frame(Store = c("a", "b", "c", "d", "e"), Lat = c(21.244769, 9.919337, 10.053961, 13.829922, 23.849729),
Long = c(81.63861, 78.14844, 76.32757, 77.49369, 77.93647))
library(tidyverse)
a1 <- a %>%
group_by(Lat, Long) %>%
summarise(closest = which.min(abs(Lat - b$Lat) + abs(Long - b$Long))) %>%
mutate(Store = b$Store[closest],
Distance = sqrt((Lat - b$Lat[closest])^2 + (Long - b$Long[closest])^2))
将导致:
a1
Lat Long closest Store Distance
<dbl> <dbl> <int> <fct> <dbl>
1 10.8 76.6 3 c 0.784
2 10.8 76.6 3 c 0.786
3 13.0 79.0 4 d 1.73
4 13.0 77.5 4 d 0.870