Gradle - 从 Eclipse 项目构建路径中排除包

Question

使用 Gradle 为 Eclipse 构建项目时，如何从构建路径中排除包？

Answer 1

文档中描述了一些示例： http://gradle.org/docs/current/dsl/org.gradle.plugins.ide.eclipse.model.EclipseClasspath.html

eclipse {

  //if you want parts of paths in resulting file to be replaced by variables (files):
  pathVariables 'GRADLE_HOME': file('/best/software/gradle'), 'TOMCAT_HOME': file('../tomcat')

  classpath {
    //you can tweak the classpath of the eclipse project by adding extra configurations:
    plusConfigurations += configurations.provided

    //you can also remove configurations from the classpath:
    minusConfigurations += configurations.someBoringConfig

    //if you don't want some classpath entries 'exported' in eclipse
    noExportConfigurations += configurations.provided

    //if you want to append extra containers:
    containers 'someFriendlyContainer', 'andYetAnotherContainer'

    //customizing the classes output directory:
    defaultOutputDir = file('build-eclipse')

    //default settings for dependencies sources/javadoc download:
    downloadSources = true
    downloadJavadoc = false
  }
}

Answer 2

如果有人仍然遇到这个问题，尽管依赖项被声明为runtimeOnly，STS仍然坚持将其放在编译类路径上。这是在 Gradle 版本 8.7 和 STS 版本 4.22 中测试的解决方案：

configurations {
    // Define a custom configuration for the dependency
    excludeFromEclipse
}

dependencies {
    // Add the dependency to the custom configuration
    excludeFromEclipse 'group:artifact:version'
}

eclipse {
    classpath {
        // Exclude the custom configuration from the Eclipse classpath
        minusConfigurations += [configurations.excludeFromEclipse]
    }
}